To find the electrostatic force between two point charges, we can use Coulomb's Law, which is mathematically expressed as:

Coulomb's Law Formula
The formula is given by:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
Where:
- \( F \) = Force between the charges (in Newtons)
- \( k \) = Coulomb's constant (\( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \))
- \( q_1 \) and \( q_2 \) = Magnitudes of the charges (in Coulombs)
- \( r \) = Distance between the charges (in meters)

Given Values
- \( q_1 = 2 \, \text{C} \)
- \( q_2 = 1 \, \text{C} \)
- \( r = 1 \, \text{m} \)

Calculation Steps
1. **Substituting the values into the formula:**
\[ F = 8.99 \times 10^9 \frac{|2 \times 1|}{1^2} \]
2. **Solving the expression:**
\[ F = 8.99 \times 10^9 \frac{2}{1} \]
\[ F = 8.99 \times 10^{9} \times 2 \]
\[ F = 17.98 \times 10^{9} \, \text{N} \]
3. **Converting to scientific notation:**
\[ F = 1.798 \times 10^{10} \, \text{N} \]

Conclusion
The force between the charges is approximately:
\[ F \approx 1.798 \times 10^{10} \, \text{N} \]
This aligns closely with the given options, but none match perfectly. However, if we consider only significant figures, the closest option is:
- b) \( 18 \times 10^6 \) N or \( 1.8 \times 10^7 \) N.
To clarify, the actual calculated force is much larger than the provided options. Please check the question's context for any discrepancies.