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If one of the zeros of quadratic polynomial (k-1)x2 + kx + 1 is -3 then the value of k?
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If one of the zeros of quadratic polynomial (k-1)x2 + kx + 1 is -3 the...
To find the value of \( k \) for which one of the zeros of the quadratic polynomial \((k-1)x^2 + kx + 1\) is \(-3\), we can follow these steps:

Step 1: Substitute the zero into the polynomial
- We know that if \(-3\) is a zero, then substituting \(-3\) into the polynomial must yield zero:
\[
(k-1)(-3)^2 + k(-3) + 1 = 0
\]

Step 2: Simplify the equation
- Now, simplify the equation:
- Calculate \((-3)^2\):
\[
9(k-1) - 3k + 1 = 0
\]
- Expand and combine like terms:
\[
9k - 9 - 3k + 1 = 0
\]
\[
6k - 8 = 0
\]

Step 3: Solve for \( k \)
- Rearranging the equation gives:
\[
6k = 8
\]
\[
k = \frac{8}{6} = \frac{4}{3}
\]

Conclusion
- Therefore, the value of \( k \) such that one of the zeros of the polynomial is \(-3\) is:
\[
k = \frac{4}{3}
\]
This process shows how substituting a known zero into the polynomial leads to determining the required parameter \( k \).
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If one of the zeros of quadratic polynomial (k-1)x2 + kx + 1 is -3 then the value of k?
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