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In uniform distribution random variable xiims only the value eight nine 11 15 18 20 then p of x is equal to 9 each?
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In uniform distribution random variable xiims only the value eight nin...
Understanding Uniform Distribution
Uniform distribution is a type of probability distribution where every outcome has an equal chance of occurring. When we have a discrete set of values, such as 8, 9, 11, 15, 18, and 20, we can analyze the probability of each value.

Given Values
- The random variable \( X \) can take the values:
- 8
- 9
- 11
- 15
- 18
- 20

Total Outcomes
- There are **6 distinct outcomes** in this case.

Calculating Probability
- In a uniform distribution, the probability of each outcome is calculated as:
\[
P(X = x_i) = \frac{1}{n}
\]
- Here, \( n \) is the total number of outcomes. Thus:
\[
P(X = 8) = P(X = 9) = P(X = 11) = P(X = 15) = P(X = 18) = P(X = 20) = \frac{1}{6}
\]

Conclusion
- Hence, the probability of each value, including \( P(X = 9) \), is **1/6** or approximately **0.1667**.
- This means that each value from the set has an equal likelihood of occurring, confirming the principle of uniform distribution.

Key Takeaway
- All values in this uniform distribution, including 9, indeed share the same probability, which is **1/6**.
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In uniform distribution random variable xiims only the value eight nine 11 15 18 20 then p of x is equal to 9 each?
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