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5 cot2 A – 5 cosec2 A =
  • a)
    – 5
  • b)
    1
  • c)
    0
  • d)
    5
Correct answer is option 'A'. Can you explain this answer?
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5 cot2 A – 5 cosec2 A =a)– 5b)1c)0d)5Correct answer is opt...
Given: 5cot²A × 5cosec²A
To find: the value of the expression

Solution:
We know that:
cot²A = 1/(tan²A) and cosec²A = 1/(sin²A)
Substituting these values in the given expression, we get:
5cot²A × 5cosec²A = 5(1/(tan²A)) × 5(1/(sin²A))
= 25/(tan²A × sin²A)

But we know that:
tan²A × sin²A = (sinA/cosA)² × sin²A = sin³A/cos²A
Substituting this value in the expression, we get:
25/(tan²A × sin²A) = 25/(sin³A/cos²A)
= 25(cos²A/sin³A)
= 25cot²A × cosec²A

Substituting the values of cot²A and cosec²A, we get:
25cot²A × cosec²A = 25(1/(tan²A)) × 5(1/(sin²A))
= 25/(tan²A × sin²A)

We can see that this is the same expression that we started with.
Therefore, 5cot²A × 5cosec²A = 25/(tan²A × sin²A)

Answer: Option A) 5
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5 cot2 A – 5 cosec2 A =a)– 5b)1c)0d)5Correct answer is opt...
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5 cot2 A – 5 cosec2 A =a)– 5b)1c)0d)5Correct answer is option 'A'. Can you explain this answer?
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