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Taxi fare in city is such that 50 rupees is fixed amount and 16 rupees per km is charged.
Taking the distance covered as x km and total fare as y rupees,write a linear equation in x and y.?
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Taxi fare in city is such that 50 rupees is fixed amount and 16 rupees...
Understanding Taxi Fare Structure
In the city, the taxi fare consists of a fixed charge and a variable charge based on distance traveled. To formulate a linear equation representing this fare structure, we need to identify the key components involved.
Components of the Fare
- Fixed Charge: The taxi begins with a fixed charge of 50 rupees. This means that regardless of the distance traveled, this amount will always be added to the fare.
- Variable Charge: For every kilometer traveled, 16 rupees is charged. This variable cost increases with the distance covered.
Formulating the Equation
To express the total fare (y) as a function of the distance covered (x), we can combine the fixed and variable charges:
- Total Fare (y) = Fixed Charge + (Variable Charge per km × Distance traveled)
This leads us to the equation:
y = 50 + 16x
Here,
- y represents the total fare in rupees,
- x represents the distance traveled in kilometers.
Characteristics of the Equation
- Linear Relationship: The equation is linear, indicating that as the distance (x) increases, the total fare (y) increases proportionately.
- Slope and Intercept: The slope of the line is 16, which signifies the rate of change of fare with respect to distance. The y-intercept is 50, representing the fixed charge.
Conclusion
This linear equation effectively captures the taxi fare structure in the city, allowing for easy calculations of fares based on varying distances. Understanding this relationship is crucial for both passengers and taxi operators.
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Taxi fare in city is such that 50 rupees is fixed amount and 16 rupees per km is charged.Taking the distance covered as x km and total fare as y rupees,write a linear equation in x and y.?
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