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The general solution of (x2 D2 – xD), y= 0 is :
- a)y = C1 + C2 ex
- b)y = C1 + C2 x
- c)y = C1 + C2 x2
- d)y = C1 x + C2 x2
Correct answer is option 'C'. Can you explain this answer?
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The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C...
This is a homogeneous eqn. let x=e^z this implies that z= logx D=d/dz let xD = D1 x²D²=D1(D1-1) so eqn. 1 becomes [D1(D1-1) -D1]y=0 D1² - 2D1]y=0 now auxiliary eqn. is m² - 2m=0 m(m - 2)=0 m=0,2 so y= C1e^0z + C2 e^2z since x=e^z so y=C1+C2 x²
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Community Answer
The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C...
+ 4xD + 3y = 0) is:
y = c1e-x + c2e-3x
Where c1 and c2 are constants determined by the initial conditions of the problem.
y = c1e-x + c2e-3x
Where c1 and c2 are constants determined by the initial conditions of the problem.
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The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer?
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The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? for Engineering Mathematics 2024 is part of Engineering Mathematics preparation. The Question and answers have been prepared according to the Engineering Mathematics exam syllabus. Information about The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Engineering Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer?.
The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? for Engineering Mathematics 2024 is part of Engineering Mathematics preparation. The Question and answers have been prepared according to the Engineering Mathematics exam syllabus. Information about The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Engineering Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer?.
Solutions for The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Engineering Mathematics .
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The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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