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Prove that the sum of any two sides of a triangle is greater than the third side?
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Prove that the sum of any two sides of a triangle is greater than the ...
Understanding the Triangle Inequality Theorem
The triangle inequality theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the remaining side. Here’s a detailed breakdown of the proof.
Proof Using a Geometric Approach
1. Consider a Triangle:
Let triangle ABC have sides AB, BC, and CA with lengths denoted as a, b, and c respectively.
2. Positioning the Triangle:
Place triangle ABC on a coordinate plane with vertices at:
- A(0,0)
- B(a,0)
- C(x,y), where x and y satisfy the conditions for triangle formation.
3. Applying the Distance Formula:
The lengths of the sides can be calculated as:
- AB = a
- BC = √[(x - a)² + (y - 0)²]
- CA = √[(x - 0)² + (y - 0)²]
4. Demonstrating the Inequality:
To prove that a + b > c, we consider the following:
- Draw a line segment from A to C.
- The direct distance AC must be less than the sum of the distances AB and BC. This visualizes why the sum of two sides must exceed the third.
Conclusion
In essence, if we were to align the triangle’s sides, the combined lengths of two sides would always stretch beyond the length of the third side, confirming that:
- a + b > c
- b + c > a
- c + a > b
This property ensures the integrity and existence of a triangle, solidifying the triangle inequality theorem’s foundational role in geometry.
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Prove that the sum of any two sides of a triangle is greater than the third side?
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