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The diagonals of rhombus ABCD intersect at O taking O as the centre and arc of radius 6 cm is drawn intersecting oa and OD at E and F respectively the area of the sector OEF is?
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The diagonals of rhombus ABCD intersect at O taking O as the centre an...
Understanding the Problem
To find the area of the sector OEF formed by the radius extending from point O to points E and F on a rhombus, we need to follow these steps:
Step 1: Identify Key Components
- Radius (r): Given as 6 cm.
- Sector OEF: This is the area we want to calculate.
Step 2: Determine the Angle
To find the area of the sector, we need the angle ∠EOF in radians. Since O is the intersection of the diagonals of rhombus ABCD, it divides the rhombus into four equal triangles. Each angle at O is 90°, as the diagonals of a rhombus bisect each other at right angles.
- Angle ∠EOF: 90° or π/2 radians.
Step 3: Calculate the Area of the Sector
The formula for the area of a sector is given by:
\[ \text{Area} = \frac{1}{2} r^2 \theta \]
Where:
- \( r \) = radius of the sector
- \( \theta \) = angle in radians
Applying the values:
- \( r = 6 \) cm
- \( \theta = \frac{\pi}{2} \)
Hence, the area becomes:
\[ \text{Area} = \frac{1}{2} \times (6)^2 \times \frac{\pi}{2} \]
\[ = \frac{1}{2} \times 36 \times \frac{\pi}{2} \]
\[ = 9\pi \, \text{cm}^2 \]
Final Result
The area of the sector OEF is \( 9\pi \, \text{cm}^2 \), which is approximately 28.27 cm² when calculated numerically.
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The diagonals of rhombus ABCD intersect at O taking O as the centre and arc of radius 6 cm is drawn intersecting oa and OD at E and F respectively the area of the sector OEF is?
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