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Solve the following quadratic equation by factorization method
1/a+b+c = 1/a + 1/b + 1/c , a+b not = to 0?
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Solve the following quadratic equation by factorization method1/a+b+c ...
Understanding the Equation
The equation given is:
1/a + b + c = 1/a + 1/b + 1/c
This can be simplified to find a common expression.
Rearranging the Equation
- Start by eliminating the common term on both sides:
1/a + b + c - (1/a + 1/b + 1/c) = 0
- This simplifies to:
b + c - (1/b + 1/c) = 0
Finding a Common Denominator
- Multiply through by abc to eliminate the denominators:
abc(b + c) - ac - ab = 0
- This can be rewritten as:
abc(b + c) = ac + ab
Factoring the Equation
- The expression can be factored as follows:
abc(b + c) - ab - ac = 0
=> ab(c - 1) + ac(b - 1) = 0
- This indicates either:
1. ab = 0 (which is not allowed, since a + b ≠ 0)
2. c - 1 = 0 or b - 1 = 0
Finding Solutions
- If c - 1 = 0, then c = 1
- If b - 1 = 0, then b = 1
Conclusion
The values of b and c can be determined from the equation. The assumption that a + b is not equal to 0 ensures that neither variable is zero, thus allowing for valid solutions.
This factorization method provides a systematic approach to solving the quadratic equation while ensuring clarity and correctness in the calculation process.
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Solve the following quadratic equation by factorization method1/a+b+c = 1/a + 1/b + 1/c , a+b not = to 0?
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