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. Out of 500 HIV patients in their ADS stage 325 were suffering from, Tuberculosis, 230 were suffering from Diarrhoea. If all the patients were suffering from at least one of them, find how many of them were suffering from both.?
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. Out of 500 HIV patients in their ADS stage 325 were suffering from, ...
To find the number of HIV patients suffering from both Tuberculosis and Diarrhoea, we will use the principle of inclusion-exclusion in set theory.
Given Information:
- Total HIV patients (A) = 500
- Patients suffering from Tuberculosis (T) = 325
- Patients suffering from Diarrhoea (D) = 230
Using Inclusion-Exclusion Principle:
According to the principle, the number of patients suffering from at least one condition (either Tuberculosis or Diarrhoea) can be expressed as:
- Total patients = Patients with Tuberculosis + Patients with Diarrhoea - Patients with both conditions
This can be formulated as:
- A = T + D - (Patients with both conditions)
Substituting Values:
Plugging in the values we have:
- 500 = 325 + 230 - (Patients with both conditions)
Combining the numbers:
- 500 = 555 - (Patients with both conditions)
Solving for Patients with Both Conditions:
Rearranging the equation gives:
- Patients with both conditions = 555 - 500
- Patients with both conditions = 55
Conclusion:
Thus, the number of HIV patients suffering from both Tuberculosis and Diarrhoea is
55.
This analysis illustrates the application of set theory in understanding overlapping conditions among patient populations, crucial for healthcare planning and resource allocation.
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. Out of 500 HIV patients in their ADS stage 325 were suffering from, Tuberculosis, 230 were suffering from Diarrhoea. If all the patients were suffering from at least one of them, find how many of them were suffering from both.?
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