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Find the perimeter of a rhombus which diagonal measures 16 cm and 30 cm?
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Find the perimeter of a rhombus which diagonal measures 16 cm and 30 c...
To find the perimeter of a rhombus given its diagonals, follow the detailed steps below.
Understanding the Rhombus
- A rhombus is a quadrilateral with all sides of equal length.
- The diagonals of a rhombus bisect each other at right angles.
Given Dimensions
- Diagonal 1 (d1) = 16 cm
- Diagonal 2 (d2) = 30 cm
Finding the Length of the Sides
1. Calculate Half of Each Diagonal:
- Half of Diagonal 1 (d1/2) = 16 cm / 2 = 8 cm
- Half of Diagonal 2 (d2/2) = 30 cm / 2 = 15 cm
2. Using the Pythagorean Theorem:
- Each side of the rhombus can be found using the formula:
\[
\text{Side} = \sqrt{(d1/2)^2 + (d2/2)^2}
\]
- Plugging in the values:
\[
\text{Side} = \sqrt{(8)^2 + (15)^2} = \sqrt{64 + 225} = \sqrt{289} = 17 \text{ cm}
\]
Calculating the Perimeter
- The perimeter (P) of a rhombus is given by:
\[
P = 4 \times \text{Side}
\]
- Therefore:
\[
P = 4 \times 17 \text{ cm} = 68 \text{ cm}
\]
Final Result
- The perimeter of the rhombus with diagonals measuring 16 cm and 30 cm is 68 cm.
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Find the perimeter of a rhombus which diagonal measures 16 cm and 30 cm?
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