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Identify the reducing agent for H2O + F2 gives HF + h o f?
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Identify the reducing agent for H2O + F2 gives HF + h o f?
Understanding the Reaction
In the reaction of water (H₂O) with fluorine (F₂) to produce hydrofluoric acid (HF) and oxygen (O₂), we can identify the reducing agent by analyzing the changes in oxidation states.
Reaction Overview
- Reactants: H₂O + F₂
- Products: HF + O₂
Oxidation States
- In H₂O, the oxidation state of hydrogen (H) is +1 and oxygen (O) is -2.
- In F₂, fluorine (F) is in the elemental state, having an oxidation state of 0.
- In HF, the oxidation state of hydrogen remains +1 while fluorine has an oxidation state of -1.
- In O₂, oxygen has an oxidation state of 0.
Identifying the Reducing Agent
- A reducing agent is a substance that donates electrons and is oxidized in the process.
- In this reaction, H₂O is oxidized to O₂, meaning it loses electrons.
- Hence, the oxidation state of oxygen increases from -2 in H₂O to 0 in O₂.
Conclusion
- Since H₂O is losing electrons (being oxidized), it acts as the reducing agent in this reaction.
- F₂, on the other hand, acts as the oxidizing agent since it gains electrons and is reduced from 0 to -1 oxidation state.
Summary
- Reducing Agent: H₂O
- Oxidizing Agent: F₂
- Products: HF and O₂
This understanding of oxidation states and electron transfer helps clarify the roles of reactants in redox reactions.
In the reaction of water (H₂O) with fluorine (F₂) to produce hydrofluoric acid (HF) and oxygen (O₂), we can identify the reducing agent by analyzing the changes in oxidation states.
Reaction Overview
- Reactants: H₂O + F₂
- Products: HF + O₂
Oxidation States
- In H₂O, the oxidation state of hydrogen (H) is +1 and oxygen (O) is -2.
- In F₂, fluorine (F) is in the elemental state, having an oxidation state of 0.
- In HF, the oxidation state of hydrogen remains +1 while fluorine has an oxidation state of -1.
- In O₂, oxygen has an oxidation state of 0.
Identifying the Reducing Agent
- A reducing agent is a substance that donates electrons and is oxidized in the process.
- In this reaction, H₂O is oxidized to O₂, meaning it loses electrons.
- Hence, the oxidation state of oxygen increases from -2 in H₂O to 0 in O₂.
Conclusion
- Since H₂O is losing electrons (being oxidized), it acts as the reducing agent in this reaction.
- F₂, on the other hand, acts as the oxidizing agent since it gains electrons and is reduced from 0 to -1 oxidation state.
Summary
- Reducing Agent: H₂O
- Oxidizing Agent: F₂
- Products: HF and O₂
This understanding of oxidation states and electron transfer helps clarify the roles of reactants in redox reactions.
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Identify the reducing agent for H2O + F2 gives HF + h o f?
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Identify the reducing agent for H2O + F2 gives HF + h o f? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Identify the reducing agent for H2O + F2 gives HF + h o f? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Identify the reducing agent for H2O + F2 gives HF + h o f?.
Identify the reducing agent for H2O + F2 gives HF + h o f? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Identify the reducing agent for H2O + F2 gives HF + h o f? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Identify the reducing agent for H2O + F2 gives HF + h o f?.
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