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Bhai ek doubt tha
Jisme piston cylinder arrangement h
Aur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe
During a constant pressure process usme 750 kj heat add krte h
To jo liquid portion h wo phase change krke vapour bn jta h
To ab btana h ki change in entropy kya hogi
Answer h ∆S= Q/T = 750/300 = 2.5 Kj/K
Pr isme phase change wla entropy kyu ni consider kia
∆S = Latent heat / Temp. (saturation)?
Jisme piston cylinder arrangement h
Aur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe
During a constant pressure process usme 750 kj heat add krte h
To jo liquid portion h wo phase change krke vapour bn jta h
To ab btana h ki change in entropy kya hogi
Answer h ∆S= Q/T = 750/300 = 2.5 Kj/K
Pr isme phase change wla entropy kyu ni consider kia
∆S = Latent heat / Temp. (saturation)?
Most Upvoted Answer
Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo...
Understanding the Scenario
In the given scenario, we have a piston-cylinder arrangement containing a mixture of water in liquid and vapor phases at 300 K. During a constant pressure process, 750 kJ of heat is added, leading to a phase change where the liquid portion transforms into vapor.
Entropy Change Calculation
The total change in entropy (∆S) during the process can be evaluated using the following components:
1. Heat Addition:
- The formula used here is:
∆S = Q / T
- Where Q = 750 kJ and T = 300 K.
- Therefore,
∆S = 750 kJ / 300 K = 2.5 kJ/K.
2. Phase Change Contribution:
- When considering phase change, especially from liquid to vapor, it is essential to account for the entropy change associated with this transition.
- The entropy change due to the phase change can be calculated using:
∆S_phase = Latent heat / T_saturation.
- This step is crucial because the latent heat represents the energy required for the phase change, which contributes to the overall entropy change.
Why Phase Change Entropy is Not Included Initially
- The initial calculation (∆S = Q/T) accounts for the total heat added to the system but does not explicitly separate the contributions from the phase change.
- The phase change entropy is typically added separately to the total entropy change because it represents a distinct mechanism of energy transfer that occurs at the saturation temperature, rather than just the heat added at a constant temperature.
Final Consideration
For an accurate assessment of the total change in entropy in your scenario, you should sum both the entropy change due to heat addition and the entropy change due to the phase transition:
∆S_total = ∆S + ∆S_phase.
This approach ensures that you capture the full thermodynamic behavior of the system during the process.
In the given scenario, we have a piston-cylinder arrangement containing a mixture of water in liquid and vapor phases at 300 K. During a constant pressure process, 750 kJ of heat is added, leading to a phase change where the liquid portion transforms into vapor.
Entropy Change Calculation
The total change in entropy (∆S) during the process can be evaluated using the following components:
1. Heat Addition:
- The formula used here is:
∆S = Q / T
- Where Q = 750 kJ and T = 300 K.
- Therefore,
∆S = 750 kJ / 300 K = 2.5 kJ/K.
2. Phase Change Contribution:
- When considering phase change, especially from liquid to vapor, it is essential to account for the entropy change associated with this transition.
- The entropy change due to the phase change can be calculated using:
∆S_phase = Latent heat / T_saturation.
- This step is crucial because the latent heat represents the energy required for the phase change, which contributes to the overall entropy change.
Why Phase Change Entropy is Not Included Initially
- The initial calculation (∆S = Q/T) accounts for the total heat added to the system but does not explicitly separate the contributions from the phase change.
- The phase change entropy is typically added separately to the total entropy change because it represents a distinct mechanism of energy transfer that occurs at the saturation temperature, rather than just the heat added at a constant temperature.
Final Consideration
For an accurate assessment of the total change in entropy in your scenario, you should sum both the entropy change due to heat addition and the entropy change due to the phase transition:
∆S_total = ∆S + ∆S_phase.
This approach ensures that you capture the full thermodynamic behavior of the system during the process.
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Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)?
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Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)?.
Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bhai ek doubt tha Jisme piston cylinder arrangement hAur water jo h wo , liquid aur vapour ke mixture me present h 300 K pe During a constant pressure process usme 750 kj heat add krte h To jo liquid portion h wo phase change krke vapour bn jta h To ab btana h ki change in entropy kya hogi Answer h ∆S= Q/T = 750/300 = 2.5 Kj/KPr isme phase change wla entropy kyu ni consider kia ∆S = Latent heat / Temp. (saturation)?.
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