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Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)?
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Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C...
Understanding the Reaction and Parameters
The reaction \( A \rightarrow R \) occurs in a packed bed where the initial concentration of \( A \) is \( \mathrm{C}_{\mathrm{A} 0} = 250 \, \mathrm{mol/m^3} \). The rate of reaction is defined by:
- \( -r_{A}^{\prime \prime \prime} = k^{\prime \prime \prime} C_{A} \)
where \( k^{\prime \prime \prime} = 0.2 \, \mathrm{m^3/(m^3 \cdot s)} \).
Gas Flow and Catalyst Details
- The gas flows downward with a velocity \( u_{0} = 0.4 \, \mathrm{m/s} \).
- The volume flow rate is \( v_{0} = 0.942 \, \mathrm{m^3/s} \).
- There are 4 tons of catalyst, and the density of the catalyst is \( \rho_{s} = 2000 \, \mathrm{kg/m^{3}} \).
Calculating the Mean Concentration of A
The mean concentration of \( A \) in the packed bed can be estimated using the concept of plug flow. In plug flow, the concentration of \( A \) decreases as it moves through the catalyst bed.
1. Total Mass of Catalyst:
- Total mass of catalyst = 4 tons = \( 4000 \, \mathrm{kg} \).
- Volume of catalyst = \( \frac{4000 \, \mathrm{kg}}{2000 \, \mathrm{kg/m^{3}}} = 2 \, \mathrm{m^{3}} \).
2. Mean Concentration Calculation:
- Mean concentration \( C_{A} \) can be calculated based on the initial concentration and the flow rate.
- Assuming no significant conversion initially, the mean concentration seen by the solids is approximately equal to the initial concentration, which is \( 250 \, \mathrm{mol/m^{3}} \).
However, considering the reaction occurring, the concentration may decrease along the bed, and adjustments may be necessary using the material balance equations for a more precise analysis.
Thus, the approximate mean concentration of \( A \) seen by the solids is around \( 250 \, \mathrm{mol/m^{3}} \), ensuring to account for any conversion as required in detailed calculations.
The reaction \( A \rightarrow R \) occurs in a packed bed where the initial concentration of \( A \) is \( \mathrm{C}_{\mathrm{A} 0} = 250 \, \mathrm{mol/m^3} \). The rate of reaction is defined by:
- \( -r_{A}^{\prime \prime \prime} = k^{\prime \prime \prime} C_{A} \)
where \( k^{\prime \prime \prime} = 0.2 \, \mathrm{m^3/(m^3 \cdot s)} \).
Gas Flow and Catalyst Details
- The gas flows downward with a velocity \( u_{0} = 0.4 \, \mathrm{m/s} \).
- The volume flow rate is \( v_{0} = 0.942 \, \mathrm{m^3/s} \).
- There are 4 tons of catalyst, and the density of the catalyst is \( \rho_{s} = 2000 \, \mathrm{kg/m^{3}} \).
Calculating the Mean Concentration of A
The mean concentration of \( A \) in the packed bed can be estimated using the concept of plug flow. In plug flow, the concentration of \( A \) decreases as it moves through the catalyst bed.
1. Total Mass of Catalyst:
- Total mass of catalyst = 4 tons = \( 4000 \, \mathrm{kg} \).
- Volume of catalyst = \( \frac{4000 \, \mathrm{kg}}{2000 \, \mathrm{kg/m^{3}}} = 2 \, \mathrm{m^{3}} \).
2. Mean Concentration Calculation:
- Mean concentration \( C_{A} \) can be calculated based on the initial concentration and the flow rate.
- Assuming no significant conversion initially, the mean concentration seen by the solids is approximately equal to the initial concentration, which is \( 250 \, \mathrm{mol/m^{3}} \).
However, considering the reaction occurring, the concentration may decrease along the bed, and adjustments may be necessary using the material balance equations for a more precise analysis.
Thus, the approximate mean concentration of \( A \) seen by the solids is around \( 250 \, \mathrm{mol/m^{3}} \), ensuring to account for any conversion as required in detailed calculations.
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Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)?
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Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)?.
Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)?.
Solutions for Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? in English & in Hindi are available as part of our courses for UPSC.
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Here you can find the meaning of Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? defined & explained in the simplest way possible. Besides giving the explanation of
Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)?, a detailed solution for Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? has been provided alongside types of Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? theory, EduRev gives you an
ample number of questions to practice Reaction \( A \rightarrow R \) with initial concentration \( \mathrm{C}_{\mathrm{A} 0}=250 \mathrm{~mol} / \mathrm{m}^{3} \) and \( -r_{A}^{\prime \prime \prime}=k^{\prime \prime \prime} C_{A} \) proceeds in a packed bed with the rate constant \( 0.2 \mathrm{~m}^{3} /\left(\mathrm{m}^{3}\right) \) catalyst s\( ) \). The gas was made to flow downward through the solids ( \( \left.\mathrm{u}_{0}=0.4 \mathrm{~m} / \mathrm{s}, \mathrm{v}_{0}=0.942 \mathrm{~m}^{3} / \mathrm{s}\right) \) containing 4 tons of catalyst \( \left(\rho_{s}=2000 \mathrm{~kg} / \mathrm{m}^{3}\right) \). Assuming plug flow of gas, the proper mean concentration of A seen by the solids would be \( \qquad \) \( \mathrm{mol} / \mathrm{m}^{3} \cdot(2) \)? tests, examples and also practice UPSC tests.
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