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A sum of money amounts to 6200 in 2 years and 3 years . the principal and the rate of interest are?
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A sum of money amounts to 6200 in 2 years and 3 years . the principal ...
Understanding the Problem
To find the principal and the rate of interest, we first note the amounts given for two different periods.
Given Information
- Amount after 2 years = 6200
- Amount after 3 years = 6200
This indicates that the interest earned in the third year is zero, implying the interest is calculated on the principal.
Calculating the Principal
- Let the principal be P.
- Let the rate of interest be R%.
Using the formula for compound interest, we express the amounts:
- For 2 years:
Amount = P(1 + R/100)^2 = 6200
- For 3 years:
Amount = P(1 + R/100)^3 = 6200
Since both amounts equal 6200, we can set up the equations:
Setting Up the Equations
- P(1 + R/100)^2 = P(1 + R/100)^3
This simplifies to:
- (1 + R/100)^2 = (1 + R/100)^3
Solving for R
- This implies:
(1 + R/100) = 1 (since we can divide by (1 + R/100)^2, assuming R is not zero).
Thus, R must be 0%.
Finding the Principal
- If R = 0%, then the principal (P) equals the amount, hence:
P = 6200.
Conclusion
- Principal = 6200
- Rate of Interest = 0%
This means that the money did not earn any interest over the two years.
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A sum of money amounts to 6200 in 2 years and 3 years . the principal and the rate of interest are?
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