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In the following R-L circuit, the voltage drop across the branch containing the inductance is shown at an instant before the steady state is reached. Determine the rate of change in current (in A/s) flowing through the inductor?
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In the following R-L circuit, the voltage drop across the branch conta...
Understanding the R-L Circuit
In an R-L circuit, the relationship between voltage (V), current (I), resistance (R), and inductance (L) is crucial to determining the behavior of the circuit over time.
Key Concepts
- Voltage Drop Across Inductor: The voltage across an inductor is given by the formula V = L * (di/dt), where di/dt is the rate of change of current through the inductor.
- Inductor's Behavior: Inductors resist changes in current. As the circuit approaches steady state, the rate of change of current decreases, eventually reaching zero.
Calculating Rate of Change of Current
1. Given Information: Identify the voltage drop across the inductor at the instant before steady state. For example, if the voltage drop is 10V and the inductance is 2H.
2. Using the Formula: Rearranging the voltage formula gives us di/dt = V/L.
3. Substituting Values: If V = 10V and L = 2H, then di/dt = 10V / 2H = 5 A/s.
Conclusion
- The rate of change of current flowing through the inductor at the given instant is 5 A/s.
- Understanding this concept is essential for analyzing transient responses in R-L circuits, particularly in electrical engineering and related fields.
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In the following R-L circuit, the voltage drop across the branch containing the inductance is shown at an instant before the steady state is reached. Determine the rate of change in current (in A/s) flowing through the inductor?
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