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A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane?
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A body of mass 5kg is at rest on inclination 60.find contact force on ...
Understanding the Problem
A body of mass 5 kg is resting on an inclined plane at an angle of 60 degrees. We need to find the contact force exerted on the body by the inclined plane.
Forces Acting on the Body
- Weight (W): The weight of the body can be calculated using the formula W = m * g, where m = 5 kg and g = 9.81 m/s².
- Normal Force (N): This is the contact force exerted by the inclined plane on the body, acting perpendicular to the surface.
Calculating Weight
- Weight (W) = 5 kg * 9.81 m/s² = 49.05 N
Resolving Forces
The weight can be resolved into two components:
- Perpendicular Component (W⊥): W⊥ = W * cos(θ)
- Parallel Component (W//): W// = W * sin(θ)
Here, θ = 60 degrees.
Calculating Components
- W⊥ = 49.05 N * cos(60°) = 49.05 N * 0.5 = 24.525 N
- W// = 49.05 N * sin(60°) = 49.05 N * (√3/2) = 49.05 N * 0.866 = 42.434 N
Finding the Normal Force
Since the body is at rest, the normal force (N) must balance the perpendicular component of the weight:
- N = W⊥ = 24.525 N
Conclusion
The contact force on the body by the inclined plane is approximately 24.53 N, acting perpendicular to the surface of the plane.
A body of mass 5 kg is resting on an inclined plane at an angle of 60 degrees. We need to find the contact force exerted on the body by the inclined plane.
Forces Acting on the Body
- Weight (W): The weight of the body can be calculated using the formula W = m * g, where m = 5 kg and g = 9.81 m/s².
- Normal Force (N): This is the contact force exerted by the inclined plane on the body, acting perpendicular to the surface.
Calculating Weight
- Weight (W) = 5 kg * 9.81 m/s² = 49.05 N
Resolving Forces
The weight can be resolved into two components:
- Perpendicular Component (W⊥): W⊥ = W * cos(θ)
- Parallel Component (W//): W// = W * sin(θ)
Here, θ = 60 degrees.
Calculating Components
- W⊥ = 49.05 N * cos(60°) = 49.05 N * 0.5 = 24.525 N
- W// = 49.05 N * sin(60°) = 49.05 N * (√3/2) = 49.05 N * 0.866 = 42.434 N
Finding the Normal Force
Since the body is at rest, the normal force (N) must balance the perpendicular component of the weight:
- N = W⊥ = 24.525 N
Conclusion
The contact force on the body by the inclined plane is approximately 24.53 N, acting perpendicular to the surface of the plane.
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A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane?
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A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane?.
A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 5kg is at rest on inclination 60.find contact force on the body by inclined plane?.
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