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A bullet weighing 10g is moving with a velocity 800 m/s after passing through a mud wall 1m thick, it's veloce decreases to 100 m/s. find average resistive force by mid wall.?
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A bullet weighing 10g is moving with a velocity 800 m/s after passing ...
Problem Overview
A bullet weighing 10g (0.01 kg) travels through a mud wall with an initial velocity of 800 m/s and slows down to 100 m/s after penetrating 1m. We need to find the average resistive force exerted by the mud wall.
Key Variables
- Mass of the bullet (m): 0.01 kg
- Initial velocity (u): 800 m/s
- Final velocity (v): 100 m/s
- Distance through the wall (s): 1 m
Calculating Change in Momentum
- Initial momentum (p_initial) = m * u = 0.01 kg * 800 m/s = 8 kg·m/s
- Final momentum (p_final) = m * v = 0.01 kg * 100 m/s = 1 kg·m/s
- Change in momentum (Δp) = p_final - p_initial = 1 kg·m/s - 8 kg·m/s = -7 kg·m/s
Calculating Time Taken
Using the formula for average velocity during the penetration:
- Average velocity (v_avg) = (u + v) / 2 = (800 m/s + 100 m/s) / 2 = 450 m/s
- Time taken (t) = s / v_avg = 1 m / 450 m/s ≈ 0.00222 s
Calculating Average Resistive Force
Using Newton's second law:
- Average force (F_avg) = Change in momentum / time = Δp / t = -7 kg·m/s / 0.00222 s ≈ -3152 N
Conclusion
The average resistive force exerted by the mud wall on the bullet is approximately 3152 N in the opposite direction of the bullet's motion. This high resistive force illustrates the significant impact of the mud wall on the bullet's velocity.
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A bullet weighing 10g is moving with a velocity 800 m/s after passing through a mud wall 1m thick, it's veloce decreases to 100 m/s. find average resistive force by mid wall.?
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