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A beam of size (250×500)mm is subjected to an factored moment (Mu) of 170kNm. determine the steel areas. Take effective cover=50mm Use M20 concrete and 415steel?
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A beam of size (250×500)mm is subjected to an factored moment (Mu) of ...
Effective Depth Calculation
To determine the effective depth (d) of the beam, we first need to calculate it using the given dimensions and effective cover.
- Total depth of the beam = 500 mm
- Effective cover = 50 mm
- Diameter of main steel bars (assume 20 mm for calculation) = 20 mm
Effective depth (d) = Total depth - Effective cover - (Diameter of bars / 2)
d = 500 - 50 - (20 / 2) = 500 - 50 - 10 = 440 mm
Design Moment Capacity
The design moment capacity (Mu) is given as 170 kNm. Using the formula for the moment capacity of a singly reinforced beam:
Mu = 0.138 * fck * b * d^2
Where:
- fck = characteristic strength of concrete (M20 = 20 MPa)
- b = width of beam = 250 mm
- d = effective depth = 440 mm
Now, converting units:
Mu = 0.138 * 20 * 250 * (440)^2 / 10^6
Mu = 0.138 * 20 * 250 * 193600 / 10^6
Mu = 1.06 kNm (approx)
Area of Steel Required
Using the equation for the area of steel (Ast):
Ast = Mu / (0.87 * fy * lever arm)
Assuming lever arm (z) = 0.95 * d:
z = 0.95 * 440 = 418 mm
Using fy = 415 MPa:
Ast = (170 * 10^3) / (0.87 * 415 * 418 / 10^6)
Ast = (170 * 10^3) / (0.87 * 0.415 * 418)
Ast = 446.56 mm²
Final Steel Area
To ensure sufficient reinforcement, we will round up and use:
- Minimum required steel area = 450 mm²
Hence, use 2 bars of 16 mm diameter or equivalent.
This design ensures the beam can safely withstand the applied moments while adhering to structural integrity standards.
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A beam of size (250×500)mm is subjected to an factored moment (Mu) of 170kNm. determine the steel areas. Take effective cover=50mm Use M20 concrete and 415steel?
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