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Find the greatest and smallest values that the function f(x, y) = xy takes on the ellipse x2 8 + y2 2 = 1?
Most Upvoted Answer
Find the greatest and smallest values that the function f(x, y) = xy t...
Understanding the Problem
To find the maximum and minimum values of the function f(x, y) = xy on the ellipse defined by the equation x^2/8 + y^2/2 = 1, we can utilize the method of Lagrange multipliers or parameterize the ellipse.
Parameterization of the Ellipse
The ellipse can be parameterized as follows:
- x = sqrt(8) * cos(θ)
- y = sqrt(2) * sin(θ)
Here, θ ranges from 0 to 2π.
Substituting into the Function
Now substitute x and y into f:
- f(θ) = (sqrt(8) * cos(θ)) * (sqrt(2) * sin(θ))
- f(θ) = sqrt(16) * cos(θ) * sin(θ)
- f(θ) = 4 * cos(θ) * sin(θ)
Using the identity sin(2θ) = 2 * sin(θ) * cos(θ):
- f(θ) = 2 * sin(2θ)
Finding Maximum and Minimum Values
To find the extrema, consider the range of sin(2θ):
- The maximum value of sin(2θ) is 1.
- The minimum value of sin(2θ) is -1.
Thus:
- Maximum: f(θ) = 2 * 1 = 2
- Minimum: f(θ) = 2 * (-1) = -2
Conclusion
- Greatest Value: 2
- Smallest Value: -2
These values of f(x, y) = xy are achieved when θ = π/4 (for the maximum) and θ = 3π/4 (for the minimum).
Community Answer
Find the greatest and smallest values that the function f(x, y) = xy t...
Find the greatest and smallest values that the function
f
(
x, y
) =
xy
takes on the ellipse
x
2/
8+
y
2/
2= 1

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Find the greatest and smallest values that the function f(x, y) = xy takes on the ellipse x2 8 + y2 2 = 1?
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