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The width of a rectangle is two-thirds its length if the perimeter is 210 m find the dimension of the rectangle?
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The width of a rectangle is two-thirds its length if the perimeter is ...
Understanding the Problem
To find the dimensions of a rectangle where the width is two-thirds of its length and the perimeter is 210 m, we can set up a mathematical representation.
Defining Variables
- Let the length of the rectangle be L meters.
- Then the width, W, can be expressed as:
W = (2/3) * L
Perimeter Formula
The perimeter (P) of a rectangle is given by the formula:
P = 2 * (L + W)
Since the perimeter is 210 m, we can substitute the values:
210 = 2 * (L + W)
Substituting Width in the Perimeter Equation
- Substitute W with (2/3) * L:
210 = 2 * (L + (2/3) * L)
- Simplify the equation:
210 = 2 * (L + (2/3)L)
210 = 2 * (5/3)L
210 = (10/3)L
Solving for Length
- Multiply both sides by 3 to eliminate the fraction:
630 = 10L
- Now, divide by 10:
L = 63 m
Finding Width
- Now, substitute L back to find W:
W = (2/3) * 63
W = 42 m
Final Dimensions
- Length (L): 63 m
- Width (W): 42 m
In conclusion, the dimensions of the rectangle are:
- Length: 63 meters
- Width: 42 meters
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The width of a rectangle is two-thirds its length if the perimeter is 210 m find the dimension of the rectangle?
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