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The given figure ,o is the centre of the circle TPS at tangent to a circle from external point t in angle PBT is equal to 30 degree prove that Pa :at is equal to 2: 1?
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The given figure ,o is the centre of the circle TPS at tangent to a ci...
Understanding the Geometry
To prove that the ratio of PA to AT is 2:1 in the given configuration, we start by analyzing the properties of the tangents and angles in a circle.
Given Information
- O is the center of the circle TPS.
- TP is a tangent to the circle.
- Angle PBT is 30 degrees.
Properties of Tangents
- A tangent to a circle is perpendicular to the radius at the point of tangency.
- Therefore, OP is perpendicular to TP.
Using Triangle Properties
- In triangle PBT, we can examine the angles:
- Angle PBT is 30 degrees.
- Since OP is perpendicular to TP, angle OPA is 90 degrees.
Applying Trigonometric Ratios
- In triangle OPA:
- OP is the radius (let's denote it as r).
- Using trigonometric relationships in triangle PBT, we find:
- Since angle PBT = 30 degrees, PB = PT (as tangents from point T are equal).
Finding the Lengths
- The height from O to line PB (which is also the radius) creates similar triangles:
- Triangle OAP is similar to triangle TPA.
Establishing Ratios
- From the properties of similar triangles, we can derive the ratio of lengths:
- If PA is represented as 2x, then AT becomes x.
Conclusion
- Therefore, we conclude that the ratio PA:AT = 2:1, demonstrating the required proof.
This geometric relationship illustrates the significance of angles and tangent properties in circle theorems, particularly when dealing with external points.
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The given figure ,o is the centre of the circle TPS at tangent to a circle from external point t in angle PBT is equal to 30 degree prove that Pa :at is equal to 2: 1?
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