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A particle of mass 6 kg have initial velocity 15m/s. A constant force of 30N applied on the object along the direction of velocity, for 8 second.
Find
acceleration
2) displacement at 8 second
3) final velocity at 8 second
4) Initial kinetic energy
5) final kinetic energy at 8 second
6) change in kinetic energy
7) work done by force in 8 second?
Most Upvoted Answer
A particle of mass 6 kg have initial velocity 15m/s. A constant force ...
1) Acceleration
To find acceleration, use Newton's second law:
- Force (F) = mass (m) × acceleration (a)
- Here, F = 30 N and m = 6 kg.
- Rearranging gives: a = F/m = 30 N / 6 kg = 5 m/s².
2) Displacement at 8 seconds
Use the formula for displacement under constant acceleration:
- Displacement (s) = initial velocity (u) × time (t) + 0.5 × acceleration (a) × t²
- Here, u = 15 m/s, a = 5 m/s², t = 8 s.
- So, s = 15 m/s × 8 s + 0.5 × 5 m/s² × (8 s)² = 120 m + 160 m = 280 m.
3) Final Velocity at 8 seconds
Final velocity can be calculated using:
- Final velocity (v) = initial velocity (u) + acceleration (a) × time (t)
- v = 15 m/s + 5 m/s² × 8 s = 15 m/s + 40 m/s = 55 m/s.
4) Initial Kinetic Energy
Kinetic energy (KE) is calculated as:
- KE_initial = 0.5 × mass (m) × velocity² (u²)
- KE_initial = 0.5 × 6 kg × (15 m/s)² = 675 J.
5) Final Kinetic Energy at 8 seconds
KE_final is given by:
- KE_final = 0.5 × m × v²
- KE_final = 0.5 × 6 kg × (55 m/s)² = 9,075 J.
6) Change in Kinetic Energy
Change in kinetic energy is:
- ΔKE = KE_final - KE_initial = 9,075 J - 675 J = 8,400 J.
7) Work Done by Force in 8 seconds
Work done (W) is equal to the change in kinetic energy:
- W = ΔKE = 8,400 J.
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A particle of mass 6 kg have initial velocity 15m/s. A constant force of 30N applied on the object along the direction of velocity, for 8 second.Find acceleration 2) displacement at 8 second 3) final velocity at 8 second 4) Initial kinetic energy 5) final kinetic energy at 8 second 6) change in kinetic energy 7) work done by force in 8 second?
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A particle of mass 6 kg have initial velocity 15m/s. A constant force of 30N applied on the object along the direction of velocity, for 8 second.Find acceleration 2) displacement at 8 second 3) final velocity at 8 second 4) Initial kinetic energy 5) final kinetic energy at 8 second 6) change in kinetic energy 7) work done by force in 8 second? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A particle of mass 6 kg have initial velocity 15m/s. A constant force of 30N applied on the object along the direction of velocity, for 8 second.Find acceleration 2) displacement at 8 second 3) final velocity at 8 second 4) Initial kinetic energy 5) final kinetic energy at 8 second 6) change in kinetic energy 7) work done by force in 8 second? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass 6 kg have initial velocity 15m/s. A constant force of 30N applied on the object along the direction of velocity, for 8 second.Find acceleration 2) displacement at 8 second 3) final velocity at 8 second 4) Initial kinetic energy 5) final kinetic energy at 8 second 6) change in kinetic energy 7) work done by force in 8 second?.
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