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Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50?
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Q11) At time t=0, a truck travelling along a straight road at a consta...
Initial Conditions
- The truck travels at a constant speed of 72 km/hr, which converts to 20 m/s (72 km/hr * 1000m/3600s).
- The car accelerates at 1 m/s² starting from an unknown initial speed.
Overtaking Scenario
- The truck covers a distance of 0.6 km (600 m) before the car overtakes it.
- In that time, the truck travels 600 m at 20 m/s.
- Time taken for the truck to cover 600 m:
Time = Distance / Speed = 600 m / 20 m/s = 30 seconds.
Car's Movement
- The car accelerates from its initial speed for 30 seconds. Let the initial speed of the car be "u" m/s.
- Distance covered by the car during this time can be calculated using the formula:
Distance = ut + (1/2)at².
- Here, a = 1 m/s² and t = 30 s.
- Distance covered by car = u(30) + 0.5(1)(30)² = 30u + 450 m.
Equality of Distances
- At overtaking, the distances travelled by both vehicles are equal:
30u + 450 = 600.
- Solving gives:
30u = 150 --> u = 5 m/s.
After Overtaking
- At t = 30 seconds, the car's speed becomes 5 m/s + 30 m/s = 35 m/s.
- The car continues at 35 m/s, while the truck remains at 20 m/s.
Distance Calculation at t = 50 seconds
- From t = 30 to t = 50 seconds, both vehicles travel for 20 seconds.
- Distance travelled by car in 20 seconds: 35 m/s * 20 s = 700 m.
- Distance travelled by truck in 20 seconds: 20 m/s * 20 s = 400 m.
Final Distance Between Them
- Total distance travelled by the car after 50 seconds: 600 m + 700 m = 1300 m.
- Total distance travelled by the truck after 50 seconds: 600 m + 400 m = 1000 m.
- Final distance between them: 1300 m - 1000 m = 300 m.
Thus, at t = 50 seconds, the distance between the truck and the car is 300 meters.
- The truck travels at a constant speed of 72 km/hr, which converts to 20 m/s (72 km/hr * 1000m/3600s).
- The car accelerates at 1 m/s² starting from an unknown initial speed.
Overtaking Scenario
- The truck covers a distance of 0.6 km (600 m) before the car overtakes it.
- In that time, the truck travels 600 m at 20 m/s.
- Time taken for the truck to cover 600 m:
Time = Distance / Speed = 600 m / 20 m/s = 30 seconds.
Car's Movement
- The car accelerates from its initial speed for 30 seconds. Let the initial speed of the car be "u" m/s.
- Distance covered by the car during this time can be calculated using the formula:
Distance = ut + (1/2)at².
- Here, a = 1 m/s² and t = 30 s.
- Distance covered by car = u(30) + 0.5(1)(30)² = 30u + 450 m.
Equality of Distances
- At overtaking, the distances travelled by both vehicles are equal:
30u + 450 = 600.
- Solving gives:
30u = 150 --> u = 5 m/s.
After Overtaking
- At t = 30 seconds, the car's speed becomes 5 m/s + 30 m/s = 35 m/s.
- The car continues at 35 m/s, while the truck remains at 20 m/s.
Distance Calculation at t = 50 seconds
- From t = 30 to t = 50 seconds, both vehicles travel for 20 seconds.
- Distance travelled by car in 20 seconds: 35 m/s * 20 s = 700 m.
- Distance travelled by truck in 20 seconds: 20 m/s * 20 s = 400 m.
Final Distance Between Them
- Total distance travelled by the car after 50 seconds: 600 m + 700 m = 1300 m.
- Total distance travelled by the truck after 50 seconds: 600 m + 400 m = 1000 m.
- Final distance between them: 1300 m - 1000 m = 300 m.
Thus, at t = 50 seconds, the distance between the truck and the car is 300 meters.
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Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50?
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Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50?.
Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50?.
Solutions for Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? in English & in Hindi are available as part of our courses for UPSC.
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Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50?, a detailed solution for Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? has been provided alongside types of Q11) At time t=0, a truck travelling along a straight road at a constant speed of 72 km/hr passes a car, moving in same direction at some speed. At that instant, the car starts accelerating at 1 m/s2 and overtakes the truck 0.6 km further down the road. At the moment of overtaking, car's acceleration suddenly becomes zero. Find the distance between them (in m) at time t=50? theory, EduRev gives you an
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