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The concentration of a gas in a gas air mixture is reduced from 5% to 1% (volume percent) by scrubbing the mixture with fresh water in a plate column. The water and air rates are 0.65 and 0.40 kg/m2.S respectively. If a plate efficiency of 80% is used and the equilibrium relationship obtained is Y=X, where X is the mole ratio in the liquid phase
Calculate the exit water concentration.
Calculate the number of real equilibrium stages needed.
What would the minimum flow rate of the absorbent of water needed to effect the above absorption when the gas flow rates remain unchanged?
Prove that mutual diffusivities of species A and B are equal if gas mixture is ideal when total pressure is constant?
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The concentration of a gas in a gas air mixture is reduced from 5% to ...
Exit Water Concentration Calculation
To calculate the exit water concentration, we use the absorption factor and the changes in gas concentration:
- Initial gas concentration (Y_in): 5%
- Final gas concentration (Y_out): 1%
- Water rate (L): 0.65 kg/m².s
- Air rate (G): 0.40 kg/m².s
Using the equation for absorption, we can derive:
- Concentration in water (X_out) = (Y_in - Y_out) / (1 - Y_out)
Substituting values, we find:
- X_out = (5 - 1) / (1 - 1) = 4%
Thus, the exit water concentration is 4% (volume percent).
Number of Real Equilibrium Stages
The number of real equilibrium stages (N) can be calculated using the following formula:
- N = (Y_in - Y_out) / (Y_out - Y_eq)
Where Y_eq is the equilibrium concentration, which in this case equals X. Given plate efficiency (E) is 80%, we can adjust for efficiency:
- N_real = N / E
Calculating yields the necessary number of real stages.
Minimum Flow Rate of Absorbent Water
To find the minimum flow rate (L_min) of water required to achieve the absorption:
- L_min = (G * (Y_in - Y_out)) / (Y_eq - Y_out)
This accounts for constant gas flow rates during the absorption process.
Mutual Diffusivities of Species A and B
In an ideal gas mixture at constant total pressure:
- The mutual diffusivities (D_AB) of species A and B can be shown to be equal due to the equality of mole fractions and their behavior under ideal gas laws.
- The relationship is derived from Fick's laws of diffusion and can be stated as:
- D_AB = D_BA
This equality holds true when the gases behave ideally, reflecting equal diffusivity under constant pressure conditions.
By adhering to these principles, the absorption process can be effectively managed in industrial applications.
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The concentration of a gas in a gas air mixture is reduced from 5% to 1% (volume percent) by scrubbing the mixture with fresh water in a plate column. The water and air rates are 0.65 and 0.40 kg/m2.S respectively. If a plate efficiency of 80% is used and the equilibrium relationship obtained is Y=X, where X is the mole ratio in the liquid phaseCalculate the exit water concentration.Calculate the number of real equilibrium stages needed.What would the minimum flow rate of the absorbent of water needed to effect the above absorption when the gas flow rates remain unchanged? Prove that mutual diffusivities of species A and B are equal if gas mixture is ideal when total pressure is constant?
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The concentration of a gas in a gas air mixture is reduced from 5% to 1% (volume percent) by scrubbing the mixture with fresh water in a plate column. The water and air rates are 0.65 and 0.40 kg/m2.S respectively. If a plate efficiency of 80% is used and the equilibrium relationship obtained is Y=X, where X is the mole ratio in the liquid phaseCalculate the exit water concentration.Calculate the number of real equilibrium stages needed.What would the minimum flow rate of the absorbent of water needed to effect the above absorption when the gas flow rates remain unchanged? Prove that mutual diffusivities of species A and B are equal if gas mixture is ideal when total pressure is constant? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The concentration of a gas in a gas air mixture is reduced from 5% to 1% (volume percent) by scrubbing the mixture with fresh water in a plate column. The water and air rates are 0.65 and 0.40 kg/m2.S respectively. If a plate efficiency of 80% is used and the equilibrium relationship obtained is Y=X, where X is the mole ratio in the liquid phaseCalculate the exit water concentration.Calculate the number of real equilibrium stages needed.What would the minimum flow rate of the absorbent of water needed to effect the above absorption when the gas flow rates remain unchanged? Prove that mutual diffusivities of species A and B are equal if gas mixture is ideal when total pressure is constant? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The concentration of a gas in a gas air mixture is reduced from 5% to 1% (volume percent) by scrubbing the mixture with fresh water in a plate column. The water and air rates are 0.65 and 0.40 kg/m2.S respectively. If a plate efficiency of 80% is used and the equilibrium relationship obtained is Y=X, where X is the mole ratio in the liquid phaseCalculate the exit water concentration.Calculate the number of real equilibrium stages needed.What would the minimum flow rate of the absorbent of water needed to effect the above absorption when the gas flow rates remain unchanged? Prove that mutual diffusivities of species A and B are equal if gas mixture is ideal when total pressure is constant?.
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