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Four resistors each of resistance 2.0 Ω are joined end to end to form a square ABCD
as shown in the figure below. Calculate the equivalent resistance of the combination
between A and B?
Most Upvoted Answer
Four resistors each of resistance 2.0 Ω are joined end to end to form ...
Understanding the Configuration
In the given configuration, four resistors of 2.0 Ω each are connected in the form of a square ABCD. The objective is to find the equivalent resistance between points A and B.
Visualizing the Resistors
- Resistor R1 connects A to B (2.0 Ω)
- Resistor R2 connects B to C (2.0 Ω)
- Resistor R3 connects C to D (2.0 Ω)
- Resistor R4 connects D to A (2.0 Ω)
Identifying the Pathways
When calculating the equivalent resistance between points A and B, the two pathways available are:
- Directly through R1 (2.0 Ω)
- Indirectly through R2 and R4 (R2 in series with R4)
Calculating the Indirect Pathway
1. Resistance through R2 and R4:
- R2 + R4 = 2.0 Ω + 2.0 Ω = 4.0 Ω
Combining the Resistances
Now, you have two paths:
- Path 1: Direct connection through R1 = 2.0 Ω
- Path 2: Indirect connection = 4.0 Ω
These two paths are in parallel. The formula for two resistances in parallel (R1 and R2) is:
1 / Req = 1 / R1 + 1 / R2
Substituting the values:
1 / Req = 1 / 2.0 + 1 / 4.0
Simplifying the Equation
- 1 / Req = 0.5 + 0.25
- 1 / Req = 0.75
Thus,
Req = 1 / 0.75 = 1.33 Ω
Final Result
The equivalent resistance between points A and B in the square configuration is approximately 1.33 Ω.
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Four resistors each of resistance 2.0 Ω are joined end to end to form a square ABCD as shown in the figure below. Calculate the equivalent resistance of the combination between A and B?
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