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If arithmetic mean and coefficient of variation of X are 10 and 40 for respectively then the variance of -15+3x/2?
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If arithmetic mean and coefficient of variation of X are 10 and 40 for...
Understanding the Problem
To find the variance of the transformed variable Y = -15 + (3X/2), we start with the given properties of X:
- Arithmetic Mean of X (μ) = 10
- Coefficient of Variation (CV) = 40
Key Definitions
- Coefficient of Variation (CV): CV is defined as the ratio of the standard deviation (σ) to the mean (μ) and is expressed as a percentage. Given CV = 40, we can say:
- CV = (σ/μ) * 100
- Therefore, σ = (CV/100) * μ = (40/100) * 10 = 4.
- Variance (σ²): Variance is the square of the standard deviation. Thus:
- Variance of X = σ² = 4² = 16.
Transformation of the Variable
For the transformation Y = -15 + (3X/2):
- Mean of Y: The mean of a transformed variable can be calculated as:
- Mean of Y = -15 + (3/2) * μ = -15 + (3/2) * 10 = -15 + 15 = 0.
- Variance of Y: Since variance is affected only by the scaling factor (not the constant), we have:
- Variance of Y = (scaling factor)² * Variance of X.
- Here, the scaling factor is 3/2, so:
- Variance of Y = (3/2)² * 16 = (9/4) * 16 = 36.
Conclusion
The variance of the transformed variable Y = -15 + (3X/2) is 36.
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If arithmetic mean and coefficient of variation of X are 10 and 40 for respectively then the variance of -15+3x/2?
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