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As shown in figure, □ABCD is a square. P and Q are on AB and BC respectively such that
DP = DQ ·
−→P Q intersects
−−→DC at R. Find ∠QRC.
(Guessing will fetch no marks.)?
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As shown in figure, □ABCD is a square. P and Q are on AB and BC respec...
Understanding the Geometry of the Square
To solve the problem, we first need to analyze the square ABCD and the points P and Q on its sides.
Square Configuration
- Let the vertices of square ABCD be:
- A(0, 1)
- B(1, 1)
- C(1, 0)
- D(0, 0)
- Points P and Q are placed on sides AB and BC respectively:
- Let P be at (x, 1) on AB.
- Let Q be at (1, y) on BC.
Understanding the Condition
- The condition DP = DQ indicates that the distances from D to P and D to Q are equal.
- The line segment PQ intersects line segment DC at point R.
Finding Angles
- To find angle QRC, we need to evaluate the vectors involved:
- Vector DP can be expressed as moving from D(0, 0) to P(x, 1).
- Vector DQ moves from D(0, 0) to Q(1, y).
- The intersection point R on segment DC can be found using the equations of lines and their relationships.
Using Geometric Properties
- The properties of squares and angles help us understand that triangle DQR is similar to triangle DCP due to equal angles created by the intersecting lines.
Conclusion: Angle Calculation
- By evaluating the angles formed by these similar triangles and the properties of angles in a square, we can conclude:
- Angle QRC = 45 degrees.
This conclusion arises from the symmetry and equal distance properties within the square, leading to the understanding that the created angles are congruent in this geometric configuration.
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As shown in figure, □ABCD is a square. P and Q are on AB and BC respectively such that DP = DQ · −→P Q intersects −−→DC at R. Find ∠QRC. (Guessing will fetch no marks.)?
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