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If the coefficient of friction between block of mass 5 kg and wall is 0.5 then minimum force F required to hold the block with wall is?
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If the coefficient of friction between block of mass 5 kg and wall is ...
Understanding the Problem
To determine the minimum force required to hold a 5 kg block against a wall with a coefficient of friction of 0.5, we need to analyze the forces acting on the block.
Forces Acting on the Block
- Weight of the Block: The weight (W) can be calculated using the formula:
- W = mass × gravity
- W = 5 kg × 9.8 m/s² = 49 N (approximately)
- Frictional Force: The maximum frictional force (F_friction) that can act on the block is given by:
- F_friction = coefficient of friction × normal force
- F_friction = 0.5 × N (where N is the normal force exerted by the wall)
Equilibrium Condition
To hold the block against the wall without it falling, the upward frictional force must balance the weight of the block. Therefore, we set up the equation:
- F_friction = W
- 0.5 × N = 49 N
Calculating the Normal Force
From the above equation, we can solve for the normal force (N):
- N = 49 N / 0.5
- N = 98 N
Minimum Force Required
The minimum force (F) required to hold the block against the wall must equal the normal force (N) because the wall provides this force:
- F = N
- F = 98 N
Conclusion
The minimum force required to hold the block against the wall is 98 N. This force ensures that the frictional force is sufficient to counterbalance the weight of the block, preventing it from falling.
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If the coefficient of friction between block of mass 5 kg and wall is 0.5 then minimum force F required to hold the block with wall is?
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