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Water drops fall at regular interval from a tap 5m above the ground . the third drop is leaving the tap at the instant the first drop touches the ground . how far above the ground is the second drop at that instant?
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Water drops fall at regular interval from a tap 5m above the ground . ...
Understanding the Problem
Water drops are falling from a tap that is 5 meters above the ground at regular intervals. The scenario indicates that the third drop is released at the moment the first drop touches the ground. We need to determine the height of the second drop at that specific instant.
Time for Drops to Reach the Ground
- The first drop takes time to fall from a height of 5 meters.
- Using the formula for free fall:
- Distance = 1/2 * g * t^2
- Here, g (acceleration due to gravity) is approximately 9.8 m/s².
- Setting the distance to 5 meters, we can determine the time t for the first drop:
- 5 = 1/2 * 9.8 * t^2
- This gives us t^2 = 1.02, leading to t ≈ 1.01 seconds.
Interval Between Drops
- Since the drops fall at regular intervals, we can divide the total time by the number of drops.
- The first drop has already fallen for about 1.01 seconds, the second drop was released 1.01 seconds before the first drop touched the ground, and the third drop is released at that moment.
Position of the Second Drop
- The second drop has been falling for approximately 1.01 seconds.
- Using the same free fall formula for the second drop:
- Distance fallen = 1/2 * g * (1.01)^2
- This results in approximately 5 meters.
- To find the height of the second drop above the ground:
- Height = Initial Height - Distance Fallen
- So, Height = 5 - 5 = 0 meters.
Conclusion
At the instant the first drop touches the ground, the second drop is also at the ground level (0 meters above the ground).
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Water drops fall at regular interval from a tap 5m above the ground . the third drop is leaving the tap at the instant the first drop touches the ground . how far above the ground is the second drop at that instant?
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