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The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio 7 : 8 : 9. Their present ages are
- a)(45, 50, 55)
- b)(40, 60, 50)
- c)(35, 45, 70)
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The sum of the ages of 3 persons is 150 years. 10 years ago their ages...
their 10years ago age be 7x,8x,9x
so their current age be 7x+10,8x+10,9x+10
7x+10+8x+10+9x+10=120
24x+30=150
24x=120
x=5
present age= 7x+10,8x+10,9x+10
=7(5)+10,8(5)+10,9(5)+10
=45,50,55
so their current age be 7x+10,8x+10,9x+10
7x+10+8x+10+9x+10=120
24x+30=150
24x=120
x=5
present age= 7x+10,8x+10,9x+10
=7(5)+10,8(5)+10,9(5)+10
=45,50,55
Most Upvoted Answer
The sum of the ages of 3 persons is 150 years. 10 years ago their ages...
3 years ago sum of their ages would be = (150-10×3) = 120 now, 7a+8a+9a= 120 or, 24a = 120 or,. a= 5 so, 10 years ago their ages would be, (7x5), (8×5), (9×5) current age- (35+10), (40+10), (45+10) so, answer is a.
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Community Answer
The sum of the ages of 3 persons is 150 years. 10 years ago their ages...
Given:
The sum of the ages of 3 persons = 150 years
10 years ago, their ages were in the ratio 7 : 8 : 9
To find:
Their present ages
Solution:
Let the present ages of the three persons be a, b, and c.
According to the question,
a + b + c = 150 ---------(1)
10 years ago, their ages were in the ratio 7 : 8 : 9.
Let their ages 10 years ago be x, y and z respectively.
Then, according to the question,
x + y + z = 7 + 8 + 9 = 24
Now, their present ages will be (x + 10), (y + 10) and (z + 10).
Let's assume that:
a = x + 10
b = y + 10
c = z + 10
Then we can write:
x + 10 + y + 10 + z + 10 = 150
x + y + z + 30 = 150
x + y + z = 120
Now we can write:
x:y:z = 7x:8x:9x (because 10 years ago their ages were in the ratio 7 : 8 : 9)
7x + 8x + 9x = 24
24x = 24
x = 1
So, their ages 10 years ago were:
x = 1
y = 8x = 8
z = 9x = 9
Their present ages will be:
a = x + 10 = 11
b = y + 10 = 18
c = z + 10 = 19
Therefore, their present ages are 11, 18, and 19 years.
Hence, option A is the correct answer.
The sum of the ages of 3 persons = 150 years
10 years ago, their ages were in the ratio 7 : 8 : 9
To find:
Their present ages
Solution:
Let the present ages of the three persons be a, b, and c.
According to the question,
a + b + c = 150 ---------(1)
10 years ago, their ages were in the ratio 7 : 8 : 9.
Let their ages 10 years ago be x, y and z respectively.
Then, according to the question,
x + y + z = 7 + 8 + 9 = 24
Now, their present ages will be (x + 10), (y + 10) and (z + 10).
Let's assume that:
a = x + 10
b = y + 10
c = z + 10
Then we can write:
x + 10 + y + 10 + z + 10 = 150
x + y + z + 30 = 150
x + y + z = 120
Now we can write:
x:y:z = 7x:8x:9x (because 10 years ago their ages were in the ratio 7 : 8 : 9)
7x + 8x + 9x = 24
24x = 24
x = 1
So, their ages 10 years ago were:
x = 1
y = 8x = 8
z = 9x = 9
Their present ages will be:
a = x + 10 = 11
b = y + 10 = 18
c = z + 10 = 19
Therefore, their present ages are 11, 18, and 19 years.
Hence, option A is the correct answer.
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The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio 7 : 8 : 9. Their present ages area)(45, 50, 55)b)(40, 60, 50)c)(35, 45, 70)d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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