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The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate?
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The percentage of three elements ca, c and o in the sample of caco3 ca...
Understanding the Law of Constant Proportions
The law of constant proportions states that a chemical compound always contains its constituent elements in fixed ratio by mass, regardless of the amount of the compound. In the case of calcium carbonate (CaCO3), the proportions of calcium (Ca), carbon (C), and oxygen (O) are consistent.
Elemental Composition of Calcium Carbonate
- Calcium (Ca): 40%
- Carbon (C): 12%
- Oxygen (O): 48%
Calculating Elemental Masses in 1.5 g of CaCO3
To find the mass of each element in 1.5 g of calcium carbonate, we will use the percentages provided.
1. Mass of Calcium (Ca):
- Calculation: 40% of 1.5 g
- Result: (0.40 * 1.5 g) = 0.60 g
2. Mass of Carbon (C):
- Calculation: 12% of 1.5 g
- Result: (0.12 * 1.5 g) = 0.18 g
3. Mass of Oxygen (O):
- Calculation: 48% of 1.5 g
- Result: (0.48 * 1.5 g) = 0.72 g
Summary of Elemental Weights
- Calcium (Ca): 0.60 g
- Carbon (C): 0.18 g
- Oxygen (O): 0.72 g
Conclusion
In a 1.5 g sample of calcium carbonate, according to the law of constant proportions, the weights of the elements present are:
- Calcium: 0.60 g
- Carbon: 0.18 g
- Oxygen: 0.72 g
These calculations confirm that the elemental composition remains constant in any sample of calcium carbonate.
The law of constant proportions states that a chemical compound always contains its constituent elements in fixed ratio by mass, regardless of the amount of the compound. In the case of calcium carbonate (CaCO3), the proportions of calcium (Ca), carbon (C), and oxygen (O) are consistent.
Elemental Composition of Calcium Carbonate
- Calcium (Ca): 40%
- Carbon (C): 12%
- Oxygen (O): 48%
Calculating Elemental Masses in 1.5 g of CaCO3
To find the mass of each element in 1.5 g of calcium carbonate, we will use the percentages provided.
1. Mass of Calcium (Ca):
- Calculation: 40% of 1.5 g
- Result: (0.40 * 1.5 g) = 0.60 g
2. Mass of Carbon (C):
- Calculation: 12% of 1.5 g
- Result: (0.12 * 1.5 g) = 0.18 g
3. Mass of Oxygen (O):
- Calculation: 48% of 1.5 g
- Result: (0.48 * 1.5 g) = 0.72 g
Summary of Elemental Weights
- Calcium (Ca): 0.60 g
- Carbon (C): 0.18 g
- Oxygen (O): 0.72 g
Conclusion
In a 1.5 g sample of calcium carbonate, according to the law of constant proportions, the weights of the elements present are:
- Calcium: 0.60 g
- Carbon: 0.18 g
- Oxygen: 0.72 g
These calculations confirm that the elemental composition remains constant in any sample of calcium carbonate.
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The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate?
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The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate?.
The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The percentage of three elements ca, c and o in the sample of caco3 calcium carbonate ca, is 40% c is 12% and o is 48%. if the law of constant proportion is true, what weight of these elements will be present in 1.5 g of another sample of calcium carbonate?.
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