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The are of a trapezium is 384cm2 if the parallel sides are in the ratio 3:5 and the perpendicular distance between them in 12 cm then find the smaller of the parallel side?
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The are of a trapezium is 384cm2 if the parallel sides are in the rati...
Given Data
- Area of trapezium = 384 cm²
- Ratio of parallel sides = 3:5
- Perpendicular distance between the sides (height) = 12 cm
Understanding the Area of a Trapezium
- The area (A) of a trapezium can be calculated using the formula:
A = (1/2) × (a + b) × h
where a and b are the lengths of the parallel sides, and h is the height.
Expressing Parallel Sides
- Let the lengths of the parallel sides be represented as:
a = 3x (smaller side)
b = 5x (larger side)
- Here, x is a common multiplier based on their ratio.
Substituting into the Area Formula
- Plugging the values into the area formula:
384 = (1/2) × (3x + 5x) × 12
Simplifying the Equation
- Combine the terms:
384 = (1/2) × (8x) × 12
384 = 48x
- Solving for x:
x = 384 / 48
x = 8
Finding the Lengths of Parallel Sides
- Now, substitute x back into the expressions for a and b:
a = 3x = 3 × 8 = 24 cm
b = 5x = 5 × 8 = 40 cm
Conclusion
- The smaller parallel side of the trapezium is 24 cm.
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The are of a trapezium is 384cm2 if the parallel sides are in the ratio 3:5 and the perpendicular distance between them in 12 cm then find the smaller of the parallel side?
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