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In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.?
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In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of...
Bit Rate and Symbol Rate
The bit rate of the BPSK (Binary Phase Shift Keying) sequence is 1 Mbps. In BPSK, each symbol represents one bit. Therefore, the symbol rate is equal to the bit rate.
- Symbol Rate: 1 Mbps
This means that the system transmits 1 million symbols per second.
Minimum Bandwidth Required
To determine the minimum bandwidth required for BPSK transmission, we can use the Nyquist formula for the minimum bandwidth:
- Minimum Bandwidth (B) = 2 * Symbol Rate
Substituting the symbol rate:
- Minimum Bandwidth = 2 * 1 Mbps = 2 MHz
This indicates that the minimum bandwidth required to transmit the BPSK signal without intersymbol interference is 2 MHz.
Summary
- Bit Rate: 1 Mbps
- Symbol Rate: 1 Mbps
- Minimum Bandwidth Required: 2 MHz
In conclusion, for a BPSK system with a bit rate of 1 Mbps and a carrier frequency of 100 MHz, the symbol rate remains at 1 Mbps, and the minimum bandwidth necessary for effective communication is 2 MHz. This efficient use of bandwidth allows for reliable transmission of data in digital communication systems.
The bit rate of the BPSK (Binary Phase Shift Keying) sequence is 1 Mbps. In BPSK, each symbol represents one bit. Therefore, the symbol rate is equal to the bit rate.
- Symbol Rate: 1 Mbps
This means that the system transmits 1 million symbols per second.
Minimum Bandwidth Required
To determine the minimum bandwidth required for BPSK transmission, we can use the Nyquist formula for the minimum bandwidth:
- Minimum Bandwidth (B) = 2 * Symbol Rate
Substituting the symbol rate:
- Minimum Bandwidth = 2 * 1 Mbps = 2 MHz
This indicates that the minimum bandwidth required to transmit the BPSK signal without intersymbol interference is 2 MHz.
Summary
- Bit Rate: 1 Mbps
- Symbol Rate: 1 Mbps
- Minimum Bandwidth Required: 2 MHz
In conclusion, for a BPSK system with a bit rate of 1 Mbps and a carrier frequency of 100 MHz, the symbol rate remains at 1 Mbps, and the minimum bandwidth necessary for effective communication is 2 MHz. This efficient use of bandwidth allows for reliable transmission of data in digital communication systems.
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In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.?
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In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.?.
In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In BPSK the bit rate of sequence is 1Mbps and the carrier frequency of transmission is 100Mhz. Determine symbol rate and minimum bandwidth required for communication.?.
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