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If tan square A equals to 1 + 2 tan square B then cos square A upon cos square B is equals to?
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If tan square A equals to 1 + 2 tan square B then cos square A upon co...
Problem Statement
Given the equation:
tan²A = 1 + 2tan²B
We need to find the value of cos²A / cos²B.
Step 1: Utilize the Identity
Recall the trigonometric identity:
tan²θ + 1 = sec²θ
This can be rearranged as:
sec²A = tan²A + 1 and sec²B = tan²B + 1
Step 2: Substitute the Values
From the given equation, we substitute for tan²A:
tan²A = 1 + 2tan²B
Thus,
sec²A = tan²A + 1 = (1 + 2tan²B) + 1 = 2 + 2tan²B
Step 3: Express Cosine in Terms of Tangent
Using the identity sec²θ = 1/cos²θ, we have:
cos²A = 1 / sec²A = 1 / (2 + 2tan²B) = 1 / (2(1 + tan²B))
For cos²B, we have:
cos²B = 1 / sec²B = 1 / (1 + tan²B)
Step 4: Find the Ratio
Now we can find the ratio of cos²A to cos²B:
cos²A / cos²B = (1 / (2(1 + tan²B))) / (1 / (1 + tan²B))
This simplifies to:
cos²A / cos²B = 1 / 2
Conclusion
Therefore, the final result is:
cos²A / cos²B = 1 / 2.
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