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A particle is starting from rest has an acceleration that increases linearly with time as a equal to 2T then the distance travelled in 3rd second will be?
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A particle is starting from rest has an acceleration that increases li...
To find the distance travelled by a particle in the 3rd second, we need to analyze its motion given that the acceleration increases linearly with time.
Understanding Acceleration
- The acceleration, a, is defined as a = 2T, where T is time in seconds.
- This means at T = 1s, a = 2 m/s²; at T = 2s, a = 4 m/s²; and at T = 3s, a = 6 m/s².
Finding Velocity
- To find velocity, we integrate acceleration with respect to time.
- The velocity at time T can be determined using the formula:
v(T) = ∫ a dt = ∫ 2T dt = T² + C (where C = initial velocity, which is 0 since the particle starts from rest).
- Thus, v(T) = T².
Finding Distance
- The distance travelled in the nth second can be calculated using the formula:
S(n) = v(n) - v(n-1).
- Now, we calculate the velocities:
- v(3) = 3² = 9 m/s
- v(2) = 2² = 4 m/s
- Therefore, the distance travelled in the 3rd second is:
S(3) = v(3) - v(2) = 9 m/s - 4 m/s = 5 m.
Conclusion
- The distance travelled by the particle in the 3rd second is 5 meters.
This calculation shows how the increasing acceleration affects the displacement over time.
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A particle is starting from rest has an acceleration that increases linearly with time as a equal to 2T then the distance travelled in 3rd second will be?
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