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Two wire a and b are made from the same material why a his length l and area of cross section 2A while while b has length to l and area of cross section a divided by 2 find the ratio of the resistance of a to that of b?
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Two wire a and b are made from the same material why a his length l an...
Understanding Resistance
The resistance (R) of a wire can be calculated using the formula:
R = ρ * (L/A)
where:
- ρ = resistivity of the material
- L = length of the wire
- A = area of cross-section
Wire A Specifications
- Length (L) = l
- Area of cross-section (A) = 2A
Using the formula for resistance:
R_a = ρ * (l / (2A))
Wire B Specifications
- Length (L) = 2l
- Area of cross-section (A) = A/2
Using the same formula for resistance:
R_b = ρ * (2l / (A/2))
Calculating Resistance of Wire B
To simplify R_b:
R_b = ρ * (2l * 2/A)
R_b = ρ * (4l / A)
Finding the Ratio of Resistances
To find the ratio R_a to R_b:
R_a / R_b = (ρ * (l / (2A))) / (ρ * (4l / A))
The ρ and l cancel out:
= (1 / (2A)) / (4 / A)
This simplifies to:
= 1 / 8
Final Ratio
The ratio of the resistance of wire A to wire B is:
R_a : R_b = 1 : 8
Conclusion
Thus, the resistance of wire A is 1/8th that of wire B, indicating that wire A is significantly less resistive compared to wire B due to its larger area and shorter length.
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Two wire a and b are made from the same material why a his length l and area of cross section 2A while while b has length to l and area of cross section a divided by 2 find the ratio of the resistance of a to that of b?
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