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What mass of sodium acetate is required to make 200 ml of 0.245 molar aqueous solution?
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What mass of sodium acetate is required to make 200 ml of 0.245 molar ...
Objective
To determine the mass of sodium acetate needed to prepare 200 ml of a 0.245 M solution.
Step 1: Calculate the Number of Moles
- Volume of Solution: 200 ml = 0.200 L
- Molarity (M): 0.245 mol/L
- Formula: Moles = Molarity × Volume
- Calculation:
- Moles = 0.245 mol/L × 0.200 L = 0.049 moles
Step 2: Determine the Molar Mass of Sodium Acetate
- Chemical Formula: CH3COONa
- Atomic Masses:
- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol
- Oxygen (O): 16.00 g/mol
- Sodium (Na): 22.99 g/mol
- Calculation of Molar Mass:
- Molar Mass = (2 × 12.01) + (3 × 1.01) + (2 × 16.00) + 22.99
- Molar Mass = 82.03 g/mol
Step 3: Calculate the Mass of Sodium Acetate
- Formula: Mass = Moles × Molar Mass
- Calculation:
- Mass = 0.049 moles × 82.03 g/mol = 4.02 g
Conclusion
To prepare 200 ml of a 0.245 M sodium acetate solution, you will need approximately 4.02 grams of sodium acetate. Make sure to accurately weigh the sodium acetate and dissolve it in the appropriate volume of distilled water to achieve the desired molarity.
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What mass of sodium acetate is required to make 200 ml of 0.245 molar aqueous solution?
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