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The eccentricity of an ellipse whose latus rectum is equal to distance between foci is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The eccentricity of an ellipse whose latus rectum is equal to distance...
Distance between the foci of an ellipse = length of latus rectum
i.e.  (2b2)/a=2ae
e=b2/a2
But e=[1−b2/a2]1/2
Then e=(1−e)1/2
Squaring both sides, we get
e+e−1=0
e=−1 ± (1 + 4)1/2]/2
(∵ Eccentricity cannot be negative)
e=[(5)1/2 − 1]/2
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The eccentricity of an ellipse whose latus rectum is equal to distance...
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The eccentricity of an ellipse whose latus rectum is equal to distance...
Because latus rectum of hyperbola is a line segment perpendicular to the transverse axis through any of the foci and whose end points lie on the hyperbola
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The eccentricity of an ellipse whose latus rectum is equal to distance between foci is:a)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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