UPSC Exam > UPSC Questions > An impedance of (10+j15)ohm is connected in p...
Start Learning for Free
An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply?
Most Upvoted Answer
An impedance of (10+j15)ohm is connected in parallel with an impedance...
Total Impedance Calculation
To find the total impedance (Z_total) of two impedances in parallel, use the formula:
1/Z_total = 1/Z1 + 1/Z2
Given:
- Z1 = 10 + j15 ohm
- Z2 = 6 - j8 ohm
Calculating the admittance:
1. Convert Z1 and Z2 to admittance:
- Y1 = 1/Z1
- Y2 = 1/Z2
2. Calculate Y1 and Y2:
- Y1 = (10 - j15) / (10^2 + 15^2) = (10 - j15) / 325
- Y2 = (6 + j8) / (6^2 + 8^2) = (6 + j8) / 100
3. Add Y1 and Y2 to find Y_total.
Calculating Current and Voltage
- Given total current (I_total) = 15 A.
- Using Ohm's law, V = I * Z_total can be rearranged to calculate voltage (V):
V = I_total * Z_total
Substituting I_total into the equation will give the voltage across the parallel combination.
Calculating Power
1. The total apparent power (S) can be calculated as:
S = V * I*
2. Calculate real power (P):
P = V * I * cos(θ), where θ is the phase angle of the total impedance.
3. Find the real part of Z_total to calculate the active power.
Conclusion
By calculating V and P, you can determine the power supplied from the source. This method combines the principles of complex impedance in AC circuits, applying parallel impedance calculations and power formulas to find the required values.
To find the total impedance (Z_total) of two impedances in parallel, use the formula:
1/Z_total = 1/Z1 + 1/Z2
Given:
- Z1 = 10 + j15 ohm
- Z2 = 6 - j8 ohm
Calculating the admittance:
1. Convert Z1 and Z2 to admittance:
- Y1 = 1/Z1
- Y2 = 1/Z2
2. Calculate Y1 and Y2:
- Y1 = (10 - j15) / (10^2 + 15^2) = (10 - j15) / 325
- Y2 = (6 + j8) / (6^2 + 8^2) = (6 + j8) / 100
3. Add Y1 and Y2 to find Y_total.
Calculating Current and Voltage
- Given total current (I_total) = 15 A.
- Using Ohm's law, V = I * Z_total can be rearranged to calculate voltage (V):
V = I_total * Z_total
Substituting I_total into the equation will give the voltage across the parallel combination.
Calculating Power
1. The total apparent power (S) can be calculated as:
S = V * I*
2. Calculate real power (P):
P = V * I * cos(θ), where θ is the phase angle of the total impedance.
3. Find the real part of Z_total to calculate the active power.
Conclusion
By calculating V and P, you can determine the power supplied from the source. This method combines the principles of complex impedance in AC circuits, applying parallel impedance calculations and power formulas to find the required values.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply?
Question Description
An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply?.
An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply?.
Solutions for An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? defined & explained in the simplest way possible. Besides giving the explanation of
An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply?, a detailed solution for An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? has been provided alongside types of An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? theory, EduRev gives you an
ample number of questions to practice An impedance of (10+j15)ohm is connected in parallel with an impedance of (6-j8)ohm the total current is 15amphs calculate the power from the supply? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup