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17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample
water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]?
water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]?
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17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness...
Introduction
To determine the hardness of the water sample, we will use the EDTA titration technique. The volume and molarity of the EDTA solution used for titration will help us calculate the hardness expressed in terms of CaCO3.
Given Data
- Volume of EDTA solution = 10 ml = 0.01 M
- Volume of water sample = 50 ml
- Equivalent weight of CaCO3 = 50
Calculating the Moles of EDTA
- Moles of EDTA = Molarity × Volume (in liters)
- Moles of EDTA = 0.01 M × (10 ml / 1000) = 0.0001 moles
Hardness Calculation
- Each mole of EDTA can bind with one mole of CaCO3, thus:
- Moles of CaCO3 = Moles of EDTA = 0.0001 moles
- Now calculating the mass of CaCO3:
- Mass of CaCO3 = Moles × Equivalent weight
- Mass of CaCO3 = 0.0001 moles × 50 g/mole = 0.005 g
Calculating Hardness in Terms of mg/L
- First, convert the mass of CaCO3 to mg:
- 0.005 g = 5 mg
- Since the sample volume is 50 ml, to find hardness in mg/L:
- Hardness (mg/L) = (Mass of CaCO3 in mg) × (1000 ml / Volume of sample in ml)
- Hardness (mg/L) = 5 mg × (1000 ml / 50 ml) = 100 mg/L
Conclusion
The hardness of the water sample is 100 mg/L as CaCO3. This value indicates the amount of calcium and magnesium ions present in the water, reflecting its hardness level.
To determine the hardness of the water sample, we will use the EDTA titration technique. The volume and molarity of the EDTA solution used for titration will help us calculate the hardness expressed in terms of CaCO3.
Given Data
- Volume of EDTA solution = 10 ml = 0.01 M
- Volume of water sample = 50 ml
- Equivalent weight of CaCO3 = 50
Calculating the Moles of EDTA
- Moles of EDTA = Molarity × Volume (in liters)
- Moles of EDTA = 0.01 M × (10 ml / 1000) = 0.0001 moles
Hardness Calculation
- Each mole of EDTA can bind with one mole of CaCO3, thus:
- Moles of CaCO3 = Moles of EDTA = 0.0001 moles
- Now calculating the mass of CaCO3:
- Mass of CaCO3 = Moles × Equivalent weight
- Mass of CaCO3 = 0.0001 moles × 50 g/mole = 0.005 g
Calculating Hardness in Terms of mg/L
- First, convert the mass of CaCO3 to mg:
- 0.005 g = 5 mg
- Since the sample volume is 50 ml, to find hardness in mg/L:
- Hardness (mg/L) = (Mass of CaCO3 in mg) × (1000 ml / Volume of sample in ml)
- Hardness (mg/L) = 5 mg × (1000 ml / 50 ml) = 100 mg/L
Conclusion
The hardness of the water sample is 100 mg/L as CaCO3. This value indicates the amount of calcium and magnesium ions present in the water, reflecting its hardness level.
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17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]?
Question Description
17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]?.
17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 17. 10 ml of 0.01(M) EDTA solution required to neutralize the hardness of 50 ml sample water. Find the hardness of the sample. [Equivalent wt of CaCO3=50]?.
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