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A uniform square plate ABCD has mass of 10 kg. If two points of masses 3 kg each are placed at the corners C and D as shown in fig. then the centre of mass shifts to the point which lie on?
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A uniform square plate ABCD has mass of 10 kg. If two points of masses...
Understanding the System
The system consists of a uniform square plate ABCD with mass 10 kg and two point masses of 3 kg each placed at corners C and D. To find the new center of mass, we can use the concept of the center of mass (COM) for a system of particles.
Coordinates of the Plate and Masses
- Assume the square plate has its corners at the following coordinates:
- A(0, 0)
- B(1, 0)
- C(1, 1)
- D(0, 1)
- The mass of the plate is uniformly distributed, so the center of mass of the plate (without added masses) is at:
- COM of Plate = (0.5, 0.5)
- The point masses are located at:
- Mass at C = 3 kg
- Mass at D = 3 kg
Calculating the New Center of Mass
- The total mass of the system is:
- Total Mass = 10 kg (plate) + 3 kg (C) + 3 kg (D) = 16 kg
- The x-coordinate of the new COM is calculated as:
- X_COM = (10 kg * 0.5 + 3 kg * 1 + 3 kg * 0) / 16 kg
- X_COM = (5 + 3) / 16 = 0.5
- The y-coordinate of the new COM is:
- Y_COM = (10 kg * 0.5 + 3 kg * 1 + 3 kg * 1) / 16 kg
- Y_COM = (5 + 3 + 3) / 16 = 0.6875
Conclusion
The new center of mass of the system lies at the coordinates (0.5, 0.6875). This indicates a shift upward due to the additional masses placed at corners C and D, which increases the influence on the overall center of mass in the vertical direction.
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A uniform square plate ABCD has mass of 10 kg. If two points of masses 3 kg each are placed at the corners C and D as shown in fig. then the centre of mass shifts to the point which lie on?
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