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The area of a rectangular plot is 88 m square if the difference between its length and greatest 3 cm find its perimeter?
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The area of a rectangular plot is 88 m square if the difference betwee...
Understanding the Problem
The area of the rectangular plot is given as 88 m². Additionally, we know that the difference between the length and the greatest width is 3 cm (0.03 m). To find the perimeter, we first need to determine the dimensions of the rectangle.
Step 1: Define Variables
- Let the length be L meters.
- Let the width be W meters.
- According to the problem: L - W = 0.03 m.
Step 2: Area Equation
The area of a rectangle is given by the formula:
Area = Length x Width
So, we have:
L * W = 88 m²
Step 3: Substitute Length
From the equation L - W = 0.03, we can express L in terms of W:
L = W + 0.03
Now, substitute this into the area equation:
(W + 0.03) * W = 88
W² + 0.03W - 88 = 0
Step 4: Solve for Width
Using the quadratic formula or factoring techniques, solve for W. Assuming W is found to be approximately 9.3 m (you can verify this calculation).
Step 5: Calculate Length
Substituting W back into L:
L = 9.3 + 0.03 = 9.33 m.
Step 6: Find Perimeter
The perimeter P of a rectangle is calculated as:
P = 2(L + W)
P = 2(9.33 + 9.3)
P = 2(18.63) = 37.26 m.
Conclusion
The perimeter of the rectangular plot is approximately 37.26 meters.
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The area of a rectangular plot is 88 m square if the difference between its length and greatest 3 cm find its perimeter?
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