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What will be the probable value of mean deviation? When Q3 = 40 and Q1 = 15
- a)17.50
- b)18.75
- c)15.00
- d)None of the above
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What will be the probable value of mean deviation? When Q3= 40 and Q1=...
Q3-Q1/2
40-15/2=12.5
As we know,
6Q.D=5M.D=4S.D
.•. 6Q.D =5M.D
6×12.5/5=M.D
M.D=15
40-15/2=12.5
As we know,
6Q.D=5M.D=4S.D
.•. 6Q.D =5M.D
6×12.5/5=M.D
M.D=15
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What will be the probable value of mean deviation? When Q3= 40 and Q1=...
Mean deviation is a measure of dispersion that calculates the average distance between each data point and the mean of the data set.
Formula for Mean deviation:
Mean deviation = (Σ|xi - x̄|) / n, where
xi = individual data point
x̄ = mean of the data set
n = number of data points
Given,
Q3 = 40
Q1 = 15
We can find the median of the data set by calculating the average of Q3 and Q1.
Median = (Q3 + Q1) / 2 = (40 + 15) / 2 = 27.5
Assuming the data set is symmetric, the mean of the data set will also be 27.5.
Now, we can calculate the mean deviation using the formula mentioned above.
Mean deviation = (Σ|xi - x̄|) / n
= (|40-27.5| + |15-27.5|) / 2
= (12.5 + 12.5) / 2
= 12.5
Therefore, the probable value of mean deviation is 12.5, which is option 'C'.
Formula for Mean deviation:
Mean deviation = (Σ|xi - x̄|) / n, where
xi = individual data point
x̄ = mean of the data set
n = number of data points
Given,
Q3 = 40
Q1 = 15
We can find the median of the data set by calculating the average of Q3 and Q1.
Median = (Q3 + Q1) / 2 = (40 + 15) / 2 = 27.5
Assuming the data set is symmetric, the mean of the data set will also be 27.5.
Now, we can calculate the mean deviation using the formula mentioned above.
Mean deviation = (Σ|xi - x̄|) / n
= (|40-27.5| + |15-27.5|) / 2
= (12.5 + 12.5) / 2
= 12.5
Therefore, the probable value of mean deviation is 12.5, which is option 'C'.
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What will be the probable value of mean deviation? When Q3= 40 and Q1= 15a)17.50b)18.75c)15.00d)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
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