Ladies go to X belongs to RX + 1 modulus 2 and b is equal to X belongs...
Understanding the Problem
To analyze the given statements, we need to break down the conditions:
- Set A (X belongs to RX + 1 modulus 2): This implies that the values of X are congruent to -1 mod 2. Therefore, X can take values like -1, 1, 3, 5, etc. (odd integers).
- Set B (X belongs to hourless X - 1 greater than or equal to 2): This condition indicates that X - 1 must be at least 2, which means X must be greater than or equal to 3.
Finding the Intersection
Now, let’s determine which statements are true or false based on the sets:
- Elements of Set A: Odd integers.
- Elements of Set B: X values start from 3 and include all integers greater than or equal to 3.
Common Elements
The common elements between the two sets would be odd integers that are greater than or equal to 3. These include 3, 5, 7, and so on.
Identifying the False Statement
To find which statement is not true, we need to check if any statement claims something that contradicts the intersection of Set A and Set B.
- Possible False Statement: A statement claiming that "all elements of Set A are also in Set B" would be false since Set A includes odd integers like 1, which do not satisfy the condition of Set B.
Conclusion
In conclusion, the statement that is not true would likely be the one asserting that all elements from Set A belong to Set B. The intersection allows for specific odd integers (from A) that meet the criteria of B, but not all elements of A satisfy B.
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