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How many positive three digit integers have the hundreds digit 8 and units digit 5 find the probability of selecting one such number out of all three number?
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How many positive three digit integers have the hundreds digit 8 and u...
Understanding the Problem
To solve the problem, we need to identify the three-digit integers that have specific properties:
- The hundreds digit is 8.
- The units (or ones) digit is 5.
Finding Eligible Numbers
1. Hundreds Digit: This is fixed at 8.
2. Units Digit: This is fixed at 5.
3. Tens Digit: This digit can be any digit from 0 to 9.
Thus, we can outline the eligible numbers:
- Hundreds: 8
- Tens: 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9 (total of 10 options)
- Units: 5
Calculating Total Eligible Numbers
- The total number of positive three-digit integers that meet the criteria is equal to the number of choices for the tens digit:
- Total Numbers = 10 (for tens digit)
Finding Total Three-Digit Integers
The total number of three-digit integers ranges from 100 to 999:
- Total Three-Digit Integers = 999 - 100 + 1 = 900
Calculating the Probability
- The probability of selecting a number that meets the criteria is given by:
- Probability = (Number of favorable outcomes) / (Total outcomes)
- Probability = 10 / 900 = 1 / 90
Conclusion
The total number of positive three-digit integers with the hundreds digit 8 and the units digit 5 is 10. The probability of selecting one such number from all three-digit integers is 1/90.
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How many positive three digit integers have the hundreds digit 8 and units digit 5 find the probability of selecting one such number out of all three number?
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