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Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2
At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x?
At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x?
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Ammonium carbonate solid is heated in a closed container at 100 degree...
Understanding the Reaction
When ammonium carbonate (NH4)2CO3 is heated, it dissociates into ammonia (NH3) and carbon dioxide (CO2):
- (NH4)2CO3 (s) ⇌ 2 NH3 (g) + CO2 (g)
This is a reversible reaction occurring in a closed system.
Equilibrium and Total Pressure
At equilibrium, the total pressure (P_total) is given as 4.5 atm. This pressure is the sum of the partial pressures of the gases produced:
- P_total = P_NH3 + P_CO2
Let:
- P_NH3 = 2y (since 2 moles of NH3 are produced)
- P_CO2 = y (since 1 mole of CO2 is produced)
Thus, the total pressure equation becomes:
- 2y + y = 4.5 atm
- 3y = 4.5 atm
Solving for y gives:
- y = 1.5 atm
This means:
- P_NH3 = 2y = 3.0 atm
- P_CO2 = y = 1.5 atm
Calculating Kp
The equilibrium constant Kp is expressed as:
- Kp = (P_NH3)^2 / (P_CO2)
Substituting the values:
- Kp = (3.0 atm)^2 / (1.5 atm)
- Kp = 9.0 atm² / 1.5 atm
- Kp = 6.0 atm
Conclusion
The value of x, which represents Kp, is:
- x = 6.0 atm
This detailed breakdown provides a clear understanding of the equilibrium process and the calculation of Kp for the dissociation of ammonium carbonate.
When ammonium carbonate (NH4)2CO3 is heated, it dissociates into ammonia (NH3) and carbon dioxide (CO2):
- (NH4)2CO3 (s) ⇌ 2 NH3 (g) + CO2 (g)
This is a reversible reaction occurring in a closed system.
Equilibrium and Total Pressure
At equilibrium, the total pressure (P_total) is given as 4.5 atm. This pressure is the sum of the partial pressures of the gases produced:
- P_total = P_NH3 + P_CO2
Let:
- P_NH3 = 2y (since 2 moles of NH3 are produced)
- P_CO2 = y (since 1 mole of CO2 is produced)
Thus, the total pressure equation becomes:
- 2y + y = 4.5 atm
- 3y = 4.5 atm
Solving for y gives:
- y = 1.5 atm
This means:
- P_NH3 = 2y = 3.0 atm
- P_CO2 = y = 1.5 atm
Calculating Kp
The equilibrium constant Kp is expressed as:
- Kp = (P_NH3)^2 / (P_CO2)
Substituting the values:
- Kp = (3.0 atm)^2 / (1.5 atm)
- Kp = 9.0 atm² / 1.5 atm
- Kp = 6.0 atm
Conclusion
The value of x, which represents Kp, is:
- x = 6.0 atm
This detailed breakdown provides a clear understanding of the equilibrium process and the calculation of Kp for the dissociation of ammonium carbonate.
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Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x?
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Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x?.
Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ammonium carbonate solid is heated in a closed container at 100 degree Celsius when it dissociate reversibly to give NH3 and CO2 At equilibrium the total pressure is found to be 4.5 atm . The value of kp = x atm . find the value of x?.
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