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Father is aged three times more than his son Ronir. After 8 years, he would be two and a half times of Ronit's age.After 8 years, how many times would he be of Ronit's age?
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Father is aged three times more than his son Ronir. After 8 years, he ...
Understanding the Problem
To solve the problem, we need to define the ages of Father and Ronir. Let's set:
- Ronir's current age = R
- Father's current age = 3R (as he is three times Ronir's age)
Future Ages
In 8 years, their ages will be:
- Ronir's age after 8 years = R + 8
- Father's age after 8 years = 3R + 8
The problem states that after 8 years, the father will be two and a half times Ronir's age.
Setting Up the Equation
We can set up the equation as follows:
- 3R + 8 = 2.5 * (R + 8)
Now, let's simplify the equation step by step.
Solving the Equation
1. Distributing 2.5:
- 3R + 8 = 2.5R + 20
2. Rearranging the equation:
- 3R - 2.5R = 20 - 8
- 0.5R = 12
3. Finding Ronir's current age:
- R = 12 / 0.5
- R = 24
Now, we can find the Father's age:
- Father's current age = 3R = 3 * 24 = 72
Future Ratios
In 8 years:
- Ronir's age = 24 + 8 = 32
- Father's age = 72 + 8 = 80
Now, we can determine how many times the father's age would be of Ronir's age after 8 years:
Calculating the Ratio
- Ratio = Father's age / Ronir's age = 80 / 32 = 2.5
Conclusion
After 8 years, the father will be 2.5 times Ronir's age.
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Father is aged three times more than his son Ronir. After 8 years, he would be two and a half times of Ronit's age.After 8 years, how many times would he be of Ronit's age?
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