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When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3are mutually perpendiclar, then the particle remains stationary. If the force F1 is now removed, then the acceleration of the particle is                                                          
[AIEEE 2002]
  • a)
     
  • b)
     
  • c)
     
  • d)
     
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
When forcesF1, F2, F3are acting on a particle of mass m such thatF2and...
The particle remains stationary under the acting of three forces F1,F2  and F3 , it means resultant force is zero,
Since, in second case F1 is removed (in terms of magnitude we are talking now), the forces acting are F2 and F3 the resultant of which has the mag-nitude as F1, so acceleration of particle is F1 /m in
the direction opposite to that of F1.
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Most Upvoted Answer
When forcesF1, F2, F3are acting on a particle of mass m such thatF2and...
The particle remains stationary on the application of three forces that means the resultant force is 0.

This implies

F1 = - (F2 + F3)

Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.

Therefore, the acceleration of the particle is F1/m

The correct option is A.
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When forcesF1, F2, F3are acting on a particle of mass m such thatF2andF3are mutually perpendiclar, then the particle remains stationary. If the forceF1is now removed, then the acceleration of the particle is [AIEEE 2002]a)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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