**Calculating the Bacteria Count**

To calculate the bacteria count at the end of two hours, we need to consider the initial count and the rate at which it is increasing.

Let's break down the problem step by step:

**Step 1: Understanding the Initial Count**

The problem states that the initial count of bacteria is 5,06,000. This is the starting point from which the count will increase.

**Step 2: Understanding the Growth Rate**

The problem states that the bacteria count is increasing at a rate of 2.5% per hour. This means that for every hour that passes, the count will increase by 2.5% of the current count.

**Step 3: Calculating the Growth for the First Hour**

To calculate the growth for the first hour, we need to find 2.5% of the initial count (5,06,000).

2.5% of 5,06,000 can be calculated as:

(2.5/100) * 5,06,000 = 12,650

Therefore, the bacteria count after the first hour is the initial count (5,06,000) plus the growth for the first hour (12,650):

5,06,000 + 12,650 = 5,18,650

**Step 4: Calculating the Growth for the Second Hour**

To calculate the growth for the second hour, we need to find 2.5% of the count at the end of the first hour (5,18,650).

2.5% of 5,18,650 can be calculated as:

(2.5/100) * 5,18,650 = 12,966.25

Therefore, the bacteria count after the second hour is the count at the end of the first hour (5,18,650) plus the growth for the second hour (12,966.25):

5,18,650 + 12,966.25 = 5,31,616.25

**Step 5: Rounding the Final Count**

Since the bacteria count is typically a whole number, we need to round the final count to the nearest whole number.

Rounding 5,31,616.25 to the nearest whole number gives us:

5,31,616

Therefore, the bacteria count at the end of two hours is approximately 5,31,616.

**Conclusion**

To summarize, the bacteria count at the end of two hours, starting from an initial count of 5,06,000 and increasing at a rate of 2.5% per hour, is approximately 5,31,616.

The initial count of bacteria=5,06,000. Rate of increasing=2.5%per hour bacteria increasing per hour is 5,06,000×2.5÷100=12650. 12650×2=25300. The bacteria at the end of two hours =5,06,000+25300=5,31,300